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Ostrovityanka [42]
3 years ago
15

What is the formula for diphosphorus tetrabromide

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
4 0
The chemical formula would be: P2Br4
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Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 dm3 of propane re
laiz [17]

Answer:

80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.

Explanation:

From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.

6 0
3 years ago
4. A sign in a town gives the speed limit at 50.00 km/hr. What is this speed in cm/sec?​
ivanzaharov [21]

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2 years ago
Place each statement in the column of the particle that it best describes.<br> Refer To Photo
MrRa [10]

The options are labelled as:

1     2

3    4

5    6

7    8

Protons: 1, 5, 7

Neutrons: 2, 8

Electron: 3, 4, 6

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3 years ago
Isoflavones, quercetin and anthocyanins are all what type of phytochemicals
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8 0
3 years ago
A 100.0-mL sample of 1.00 M NaOH is mixed with 50.0 mL of 1.00 M H2SO4 in a large Styrofoam coffee cup calorimeter fitted with a
worty [1.4K]

Answer:

THE ENTHALPY CHANGE IN KJ/MOLE IS +114 KJ/MOLE.

Explanation:

Heat = mass * specific heat capacity * temperature rise

Total volume = 100 + 50 = 150 mL

Total mass = density * volume

Total mass = 1 * 150 mL = 150 g

So therefore, the heat evolved during the reaction is:

Heat = 150 * 4.18 * ( 31.4 - 22.3)

Heat = 150 * 4.18 * 9.1

Heat = 5705.7 J

Equation for the reaction:

2 NaOH(aq) + H2SO4(aq) → Na2SO4(aq) + 2 H2O(l)  

From the equation, 2 moles of NaOH reacts with 1 mole of H2SO4 to produce 1 mole of Na2SO4 and 2 moles of water

50 mL of 1 M of H2SO4 contains

50 * 1 / 1000 mole of acid

= 0.05 mole of acid

The production of 1 mole of water evolved 5705.7 J of heat and hence the enthalpy changein kJ per mole will be:

0.05 mole of H2SO4 produces 5705.7 J of heat

1 mole of H2SO4 will produce 5705.7 / 0.05 J

= 114,114 J / mole

In kj/mole = 114 kJ/mole.

Hence, the enthalpy change of the reaction in kJ /mole is +114 kJ/mole.

5 0
3 years ago
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