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3 years ago

Suppose the radius of a circle is \color{purple}{8}8start color purple, 8, end color purple units. What is its circumference?

Mathematics

1 answer:

Gelneren [198K]3 years ago

7 0

Answer:

54.24

Step-by-step explanation:

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10x-2x in fewer terms

Aleks04 [339]

Answer:

Step-by-step explanations:

10x - 2x

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3 years ago

How to write 4(4*10^5) in scientific notation

Ne4ueva [31]

Answer:

16,000,000

Step-by-step explanation:

to start off your going to need to use PEMDAS (parenthesis exponents multiplication division addition subtraction)

so we are going to start IN the parenthesis the next step is doing the exponents so its going to look like this 1,000,000

rewrite the problem: 4(4×1,000,000)

use the next step in PEMDAS multiplication rewrite the problem:

4(4,000,000)

multiply: 16,000,000

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3 years ago

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tamaranim1 [39]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

5*10^5 is how many times bigger that 1*10^5

weqwewe [10]

Answer:

Step-by-step explanation:

5*10^5=500000 and 1*10^5=100000

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3 years ago

Find the 53rd term of the arithmetic sequence<br> 27,11, -5

vivado [14]

Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

3 0

3 years ago