Answer:
1.308 * 10^(-5) m
Explanation:
We apply the condition for a single slit experiment:
y = (λ * D) / a
Where y = half width of fringe
λ = wavelength of light
D = distance of slit from screen
a = width of slit
We need to find a, so we make a the subject of formula:
a = (λ * D) / y
From the question:
λ = 550 nm = 550 * 10^(-9) m
D = 0.63 m
y = 0.053 / 2 = 0.0265 m
Therefore:
a = (550 * 10^(-9) * 0.63) / 0.0265
a = 1.308 * 10^(-5) m
The width of the slit is 1.308 * 10^(-5) m
B
Opposites attract
Like poles repel
Answer:
To minimize the practical errors and improve the accuracy.
Explanation:
- Scientists take several measurements and use the average of all the measured values to minimize the practical errors due to unavoidable circumstances and be close to the true value.
- True value is the actual value of a measured parameter without any error, it is the value which is proposed in the design of a certain object.
- Variations may occur in the measurement due to wear and tear, dust and air pressure. It is almost impossible to create ideal surrounding for the measurement procedure.
Answer:
v=32.49 m/s
Explanation:
Given that
Distance ,d= 66 m
Initial speed of the car ,u = 0 m/s
Coefficient of friction ,μ = 0.8
Lets take the total mass of the car = m
The acceleration of the car is given as
a = μ g ( g= 10 m/s² )
Now by putting the values in the above equation we get
a= 0.8 x 10 m/s²
a= 8 m/s²
We know that ,final speed is given as
v²= u ²+ 2 a d
Now putting the value
v²=0² + 2 x 8 x 66
v²= 1056
v=32.49 m/s
Answer:
A) 35 ft
B) 5 ft
C) Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick
Explanation:
A) Total distance covered by the dog = 20 + 15
= 35 ft
B) Since the other distance covered by the dog before chewing the stick, after the retrieval, was in an opposite direction to the initial direction, then;
total displacement of the dog = 20 - 15
= 5 ft
C) Net displacement = distance covered by the dog to retrieve the stick + distance covered before the dog starts chewing the stick
But, displacement involves a specified direction. The distance covered before the dog starts chewing the stick was in an opposite direction to the initial direction.
Thus,
Net displacement = distance covered by the dog to retrieve the stick - distance covered before the dog starts chewing the stick
