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boyakko [2]
3 years ago
15

What is the relation between force and acceleration ?​

Physics
2 answers:
stepladder [879]3 years ago
8 0

Explanation:

Newton's second law shows that there is a direct relation ship between force and acceleration . the grater force that is applied on a object of given mass the more the accelerate. for example doubling the force in the object doubles it's acceleration.

asambeis [7]3 years ago
7 0
Newton's second law shows that there is a direct relationship between force and acceleration. The greater the force that is applied to an object of a given mass, the more the object will accelerate.
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"Compared to infrared radiation, does ultraviolet radiation have longer or shorter wavelengths? Does ultraviolet radiation have
balu736 [363]

Answer:Ultraviolet radiation has shorter wavelengths and higher energy than infrared radiation.

Explanation: Electromagnetic radiation radiations which have both electrical and magnetic properties,they can be transmitted through space or through a medium.

It includes Gamma radiation, infra-red, visible light, Ultraviolet radiation etc they occur with different wavelength, the lower the wavelength the higher the Energy dissipated per photon. According to their order of decreasing wavelength and increased energy they are classified as follows.

RADIO WAVE, MICRO WAVE, INFRA-RED, VISIBLE LIGHT, ULTRAVIOLET RAY, X-RAY, GAMMA RAYS.

5 0
3 years ago
compare to visible light, the wavelength of x-rays is shorter longer or the same and the frequency is lower higher or the same
Doss [256]

Answer:shorter higher

Explanation:Compare to visible light, the wavelength of X-rays is shorter and then frequency is higher

7 0
3 years ago
What type of circuit is illustrated?
Elis [28]
A. Parallel circuit

Short circuits are circuits that is like plugging in a USB into your computer and the other end to your iPhone, so it's not D.

Series circuits can come in all kinds of different shapes, so it's not C.

Open circuits are circuits that are opened, meaning that whenever you turn on the light and it's an open circuit, it won't work cause the two wires are not connected, meaning it's not D.

Parallel circuits are circuits that are in one straight line, just like parallel lines, meaning the answer would be A. (Look at the picture and don't get confused with the other question that's the same question and has the same answers, they both have different pictures, so look at the pictures they give you whenever they ask the question so your getting the right answer)

Hope this helped.


8 0
3 years ago
Read 2 more answers
A parallel plate capacitor with plates of area A and plate separation d is charged so that the potential difference between its
faust18 [17]

Answer:

Explanation:

Given a parallel plate capacitor of

Area=A

Distance apart =d

Potential difference, =V

If the distance is reduce to d/2

What is p.d

We know that

Q=CV

Then,

V=Q/C

Then this shows that the voltage is inversely proportional to the capacitance

Therefore,

V∝1/C

So, VC=K

Now, the capacitance of a parallel plate capacitor is given as

C= εA/d

When the distance apart is d

Then,

C1=εA/d

When the distance is half d/2

C2= εA/(d/2)

C2= 2εA/d

Then, applying

VC=K

V1 is voltage of the full capacitor V1=V

V2 is the required voltage let say V'

Then,

V1C1=V2C2

V × εA/d=V' × 2εA/d

VεA/d = 2V'εA/d

Then the εA/d cancels on both sides and remains

V=2V'

Then, V'=V/2

The potential difference is half when the distance between the parallel plate capacitor was reduce to d/2

6 0
3 years ago
Read 2 more answers
According to the work-energy theorem, the amount of work done can be determined using which formula?
torisob [31]

Answer:

W=\Delta KE= KE_f-KE_i=\frac{1}{2} \,m \,v_f^2-\frac{1}{2} \,m \,v_i^2

Explanation:

The Work-Kinetic Energy Theorem states that the work done on a particle of mass "m", equals the particle's change in Kinetic Energy (final Kinetic Energy of the particle "KE_f" minus the initial Kinetic energy of the particle "KE_i"), and it is expressed as:

W=\Delta KE= KE_f-KE_i=\frac{1}{2} \,m \,v_f^2-\frac{1}{2} \,m \,v_i^2

where we have used the explicit form of the KE of a particle of mass m and velocity v. Of course, v_f stands for the final velocity of the particle, and v_i for the particle's initial velocity.

6 0
3 years ago
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