Food in a microwave oven heats itself by absorbing
radiation in the form of radio-waves.
White objects do not absorb all wavelenghts. The statement is false
The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>
- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
![tan\alpha =\frac{30}{30}\\ \alpha =45^0](https://tex.z-dn.net/?f=tan%5Calpha%20%3D%5Cfrac%7B30%7D%7B30%7D%5C%5C%20%5Calpha%20%3D45%5E0)
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
![y-direction\\T_2sin\alpha =mg\\\\T_2=\frac{mg}{sin\alpha } =\frac{17.1*10^{-3}*9.8}{sin45} \\\\T_2=0.236N](https://tex.z-dn.net/?f=y-direction%5C%5CT_2sin%5Calpha%20%3Dmg%5C%5C%5C%5CT_2%3D%5Cfrac%7Bmg%7D%7Bsin%5Calpha%20%7D%20%3D%5Cfrac%7B17.1%2A10%5E%7B-3%7D%2A9.8%7D%7Bsin45%7D%20%5C%5C%5C%5CT_2%3D0.236N)
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
![x-direction\\T_1-T_2cos\alpha =0\\T_1=T_2cos\alpha \\T_1=0.236*cos45=0.167N](https://tex.z-dn.net/?f=x-direction%5C%5CT_1-T_2cos%5Calpha%20%3D0%5C%5CT_1%3DT_2cos%5Calpha%20%5C%5CT_1%3D0.236%2Acos45%3D0.167N)
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
brainly.com/question/28106866
#SPJ1
Answer:
7.6427m/s
Explanation:
Given:![v_a=4.7m/s, \theta_a=33.0\textdegree and \ v_b=4.5m/s](https://tex.z-dn.net/?f=v_a%3D4.7m%2Fs%2C%20%5Ctheta_a%3D33.0%5Ctextdegree%20and%20%5C%20v_b%3D4.5m%2Fs)
#Applying the conservation of momentum along the x-axis:![mv_i=mv_acos\theta_a+mv_bcos\theta_b](https://tex.z-dn.net/?f=mv_i%3Dmv_acos%5Ctheta_a%2Bmv_bcos%5Ctheta_b)
#And along y-axis:
![0=-sin\theta_a+mv_bsin\theta_b](https://tex.z-dn.net/?f=0%3D-sin%5Ctheta_a%2Bmv_bsin%5Ctheta_b)
#Solving for
:
![sin\rheta_b=\frac{v_a}{v_b}sin\theta_a=4.7/4.5\times sin33.0\textdegree\\=0.5688\\\therefore \theta_b=34.67\textdegree](https://tex.z-dn.net/?f=sin%5Crheta_b%3D%5Cfrac%7Bv_a%7D%7Bv_b%7Dsin%5Ctheta_a%3D4.7%2F4.5%5Ctimes%20sin33.0%5Ctextdegree%5C%5C%3D0.5688%5C%5C%5Ctherefore%20%5Ctheta_b%3D34.67%5Ctextdegree)
#By substitution in the x-axis equation:
![v_i=4.7cos 33.0\textdegree +4.5cos 34.67\textdegree\\=7.6427m/s](https://tex.z-dn.net/?f=v_i%3D4.7cos%2033.0%5Ctextdegree%20%2B4.5cos%2034.67%5Ctextdegree%5C%5C%3D7.6427m%2Fs)
Hence the original speed of the ball before impact is 7.6427m/s
D: Ptolemy envisioned a geocentric model, while Copernicus envisioned a heliocentric model.