Answer:
The magnitude of the impulse delivered to the baseball is 7.0 Ns
Explanation:
Given;
mass of the foul ball, m = 0.14 kg
initial velocity, u = 40 m/s
final velocity, v = 30 m/s in perpendicular direction
Impulse is given as change in momentum;
initial momentum in horizontal direction, Pi = mu
Pi = 0.14 x 40 = 5.6 Ns
final momentum in perpendicular direction, Pf = mv
Pf = 0.14 x 30
Pf = 4.2 Ns
The resultant impulse is given by;
J² = 5.6² + 4.2²
J² = 49
J = √49
J = 7.0 Ns
Therefore, the magnitude of the impulse delivered to the baseball is 7.0 Ns
Answer:
Ball will not hit bell.
Explanation:
The height of the ball is modeled by the equation h(t)= -16t²+39t
We need to find if the bell is 25 ft above the ground, will it be hit by the ball.
So we need to find maximum height of the ball.
For maximum height we have
Substituting in h(t) = -16t²+39t
Maximum height reached = h(1.22) = -16 x 1.22²+39 x 1.22 = 23.77 ft
So maximum height reached is less than height of bell.
Ball will not hit bell.
Here is the answer to the given question above. Based on the Raisin Cake Analogy, the two properties of distant galaxies that astronomers have to measure to show<span> that we live in an expanding universe are DISTANCE and SPEED. Hope this answers your question. Have a great day!</span>
Answer:
3.834 m/s
Explanation:
h = 0.750 m
vx = 5 m/s
Let the initial vertical velocity is vy.
Final vertical velocity is zero
use third equation of motion along y axis
v^2 = vy^2 - 2 x g x h
0 = vy^2 - 2 x 9.8 x 0.75
vy^2 = 14.7
vy = 3.834 m/s
Answer:
The rate clock is about
F = 8 GHz
Explanation:
f₁ = 4 G Hz , t₁ = 10 s , t₂ = 6s , f₂ = 1.2 f₁
Can organize to find the rate clock the designer build to the target so
X / 4 Ghz = 10 s , 1.2 X / Y = 6 s
X * Y = 10 s ⇒ F = 10 s
1.2 * 4 G Hz = 6 s
F = 10 * ( 1.2 * 4 G Hz ) / 6
F = 10 * ( 1.2 * 4 x 10 ⁹ Hz ) / 6
F = 8 x 10 ⁹ Hz
F = 8 GHz
