To make it soo much easier, divide top equation by 4
-x+2y=-64
now
-6y=x
sub -6y for x
-(-6y)+2y=-64
6y+2y=-64
8y=-64
divide both sides by 8
y=-8
sub back
-6y=x
-6(-8)=x
48=x
x=48
y=-8
(x,y)
(48,-8)
Answer:
y = - 10x - 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here slope m = - 10, hence
y = - 10x + c ← is the partial equation
To find c substitute (- 1, 4) into the partial equation
4 = 10 + c ⇒ c = 4 - 10 = - 6
y = - 10x - 6 ← equation of line
Answers:
B = 50
a = 10.9
c = 17.0
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Explanation:
This is a right triangle, so the acute angles are complementary, meaning they add to 90
B+40 = 90
B+40-40 = 90-40
B = 50
Also, because this is a right triangle, we can use trig ratios to compute the missing sides
tan(angle) = opposite/adjacent
tan(40) = a/13
a = 13*tan(40)
a = 10.908
a = 10.9
cos(angle) = adjacent/hypotenuse
cos(40) = 13/c
c*cos(40) = 13
c = 13/cos(40)
c = 17.0
note: make sure your calculator is in degree mode
Answer:
Part c
Step-by-step explanation:
In quadratic equations of real coefficients, the complex roots always occur in conjugate bases. It means, if, 2 + 3i is one of the roots and then the second root must be 2 - 3i.
