Answer:
About 547 grams.
Explanation:
We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.
To do so, we can use the initial value and convert it to grams using the molar mass.
Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:

Dimensional Analysis:

In conclusion, about 547 grams of copper (II) bicarbonate is produced.
Answer:
<u>2</u> Fe + <u>3</u> H2SO4 —> Fe2(SO4)3 + <u>3</u> H2
I hope I helped you^_^
Answer:
The answer to your question is 8.28 g of glucose
Explanation:
Data
Glucose (C₆H₁₂O₆) = ?
Ethanol (CH₃CH₂OH)
Carbon dioxide (CO₂) = 2.25 l
Pressure = 1 atm
T = 295°K
Reaction
C₆H₁₂O₆ ⇒ 2C₂H₅OH(l) +2CO₂(g)
- Calculate the number of moles
PV = nRT
Solve for n

Substitution

Simplification
n = 0.092
- Calculate the mass of glucose
1 mol of glucose --------------- 2 moles of carbon dioxide
x --------------- 0.092 moles
x = (0.092 x 1) / 2
x = 0.046 moles of glucose
Molecular weight of glucose = 180 g
180 g of glucose --------------- 1 mol
x g ---------------0.046 moles
x = (0.046 x 180) / 1
x = 8.28 g of glucose
<span>Saturated sodium chloride
is used to transfer the product rather than water since it is not polar and
rinsing the product with water would revert any 4-methylcyclohexene back to
4-methylcyclohexanol in the Hickman Head and thus lowering the percent yield;
using water would shift the equilibrium towards the reactants. Also
sodium chloride removes the small amount of phosphoric acid and also a small
amount of water. If one were to add water, both 4-methylcyclohexene and
phosphoric acid are partially soluble making difficult to remove the water
later; sodium chloride makes the water less reactive so easier to remove by
making the aqueous later more polar.</span>
It will behave has a conductor in high voltage