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3 years ago

The volume of a container of gas is 2.65 L and is at a temperature of 22.4°C. What is the new volume if

Chemistry

1 answer:

Kipish [7]3 years ago

7 0

Answer:

B) 3.34

Explanation:

V1/T1 = V2/T2

So V2= (T2xV1)/T1

Side note Temp for using gas law is always kelvin (Celsius +273.15)

Volume is always in Liters

So V2 = (372.6Kx2.65L)/295.55L

Which results in 3.34L

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A drag racing vehicle travels from 0 to 100 mph in 5 seconds north.what is the acceleration

arsen [322]

100mph = 100m/h

= 100m/h * 1 h/3600sec

= 0.028m/sec

= 0.028m/sec /5sec

= 0.055m/sec^2

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4 years ago

Calculate the number of joules of heat energy needed to increase the temperature of 25.0 g of metal from 21.0 ºC to 80.0 ºC. The

Harman [31]

Answer:

Q = 768.47 J

Explanation:

Given that,

Mass of the metal, m = 25 g

Initial temperature, T₁ = 21.0 ºC

Final temperature, T₂ = 80.0 ºC

The specific heat of the metal is 0.521 J/gºC.

We know that the heat released due to the change in temperature is given by :

$Q=mc\Delta T\\\\=25\times 0.521\times (80-21)\\Q=768.47\ J$

Hence, 768.47 J of heat energy will be needed.

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3 years ago

What happens if you remove all of the carbon<br> dioxide from the atmosphere?

IrinaK [193]

If we remove all Carbon Dioxide from the atmosphere then the tree's would be able to produce the oxygen we breath since the tree's breath what we breath out

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3 years ago

What substance is combination of different atoms

Furkat [3]

The substance which is a combination of different atoms is a compound.

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3 years ago

Read 2 more answers

Although coal is a complex mixture of substances, its elemental composition can be approximated by the formula <img src="https:/

Svetllana [295]

Answer:

The correct answer is option b.

Explanation:

$2C_{135}H_{96}O_9NS+313O_2\rightarrow 270CO_2+2NO_2+2SO_2+96H_2O$

Mass of coal burned = $1.00\times 10^6$ metric ton = 1.00\times 10^6\times 10^3 kg=10^9 kg[/tex]

1 metric ton = $10^3kg$

Molar mass of coal :

$135\times 12g/mol+96\times 1g/mol+9\times 16 g/mol+1\times 14 g/mol+1\times 32 g/mol=1906 g/mol=1.906 kg/mol$

1 g = 0.001 kg

Moles of coal ,n : $\frac{10^9 kg}{1.906 kg/mol}=5.247\times 10^8 mol$

If 2 moles of coal on combustion gives 270 moles of carbon dioxide than n moles of coal will give;

$5.247\times 10^8 mol\times \frac{270}{2}=7.083\times 10^{10} mol$ of carbon dioxide.

Molar mass of carbon dioxide gas = 44 g/mol = 0.044 kg/mol

Mass of $7.083\times 10^{10} mol$ of carbon dioxide:

$7.083\times 10^{10} mol\times 0.044 kg/mol=3.11\times 10^{11} kg$

5 0

4 years ago