Question

When 4.50 L of hydrogen gas react with an excess of nitrogen gas at standard temperature and pressure, how many liters of ammonia gas will be produced?
N2 (g) + 3H2 (g) yields 2NH3 (g)

Answer 1

Answer:

           3.0 L of NH₃

Solution:

The equation is as follow,

                                    N₂  +  3 H₂     →       2 NH₃

According to equation,

          67.2 L (3 mole) H₂ at STP produces  =  44.8 L (3 mole) of NH₃

So,

                            4.50 L of H₂ will produce  =  X L of NH₃

Solving for X,

                     X  =  (4.50 L × 44.8 L) ÷ 67.2 L

                     X  =  3.0 L of NH₃