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Chemistry

2 answers:

Temka [501]3 years ago

7 0

Answer: a

Explanation:

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zlopas [31]3 years ago

3 0

b) unsaturated

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A flask of fixed volume contains 1.00 mole of gaseous carbon dioxide and 88.0 g of solid carbon dioxide. The original pressure a

Ymorist [56]

Answer:275K

Explanation:

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3 years ago

A student caries out an experiment and dissolves 10.0 g of sodium bromide. NaBr, in 200g of water. What is the molality of the s

Pavel [41]

Answer:

0.485mol/kg

Explanation:

Molality is defined as the ratio of the number of moles of a solute to the kilogram of a solvent which is usually water.

Mass of NaBr = 10g

Molar mass of NaBr= 23+80=103g/mol

Mole of NaBr = mass / molar mass=10g/103g/mol= 0.097mol

Molality= Mole of a solute/ mass of solvent in kg

Mole of a solute( NaBr)= 0.097mol; mass of solvent( water in kg)= 200g. To convert to kg: 200g/1000g= 0.2kg

Molality = 0.097mol/0.2kg = 0.485mol/kg

4 0

3 years ago

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Neporo4naja [7]

Answer:

2000 L

General Formulas and Concepts:

Atomic Structure

Moles
Temperature Conversion: K = °C + 273.15

Gas Laws

Ideal Gas Law: PV = nRT

P is pressure
V is volume (in L)
n is number of moles
R is gas constant
T is temperature (in K)

Explanation:

Step 1: Define

[Given] 8.8 moles gas

[Given] 0.12 atm

[Given] 56 °C = 329.15 K

Step 2: Solve for V

Substitute in variables [Ideal Gas Law Formula]: $\displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)$
Isolate V: $\displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}$
Multiply/Divide [Cancel out units]: $\displaystyle V = 1981.7 \ L$