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Verizon [17]
4 years ago
15

Calculate the quantity 87.3 cm − 1.655 cm. _____cm

Chemistry
2 answers:
Inessa05 [86]4 years ago
7 0

Answer:

82•355

Explanation:

1•655--87•3=82•355

slava [35]4 years ago
4 0

Answer:

the answer is 85.645cm

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Show the equation how many grams of Mg(OH)2 would be produced from 4 mol KOH?
Sindrei [870]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
4 moles KOH ------------------- moles Mg(OH)₂

moles Mg(OH)₂   = 4 x 1 / 2

= 2  moles of   Mg(OH)₂

molar mass Mg(OH)₂ = 58g/mol

mass of   Mg(OH)₂ = n x mm

mass of  Mg(OH)₂ = 58 x  2

= 116 g of <span> Mg(OH)₂</span>

hope this helps!
8 0
3 years ago
Brief report on the carbon cycle
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Answer:

Explanation:

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4 0
3 years ago
Hexane and Butane are alkanes. Describe the structure of alkanes
dem82 [27]
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8 0
3 years ago
Read 2 more answers
7g of gold is heated from 17 degrees C to 42 degrees C. How much energy (heat) was used? The specific heat capacity of gold is .
wel
Heat needed=mcθ
=7×0.031×(42-17)
=5.425cal
7 0
3 years ago
A 15.75 g piece of iron absorbs 1097 joules of heat energy, and its temperature changes from 25°C to 177°C. Calculate the specif
vekshin1

The answer for the following problem is mentioned below.

Explanation:

Given:

mass of iron (m) = 15.75 grams

heat (q) = 1097 J

initial temperature (t_{1}) = 25°C

final temperature (t_{2}) = 177°C

To find:

specific heat (c)

We know;

 c = q ÷ mΔT

where;

c represents the specific heat

q represents the heat

m represents the mass

t represents the temperature

c = \frac{1097}{15.75 * (177-25)}

c = 0.45 J/kg°C

<u><em>Therefore the specific heat capacity of iron is 0.45 J/kg°C.</em></u>

8 0
4 years ago
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