All categories

3 years ago

What is the name of the molecule shown below?

Chemistry

1 answer:

Nezavi [6.7K]3 years ago

8 0

Answer:

B) Methanoic Acid

Explanation:

You might be interested in

The heat of fusion for water at its normal freezing or melting temperature is L=333 kJ/kg. How much water remains unfrozen after

Amiraneli [1.4K]

50.2 kJ = 333 kJ/kg * mass of water mass of water is 0.15075075075075075075075075075075 kg therefore mass of unfrozen water is 0.10924924924924924924924924924925 kg

5 0

3 years ago

Read 2 more answers

Why is atp an example of chemical potential energy?

marta [7]

Hello! I hope this helps

Answer: ATP ( adenosine triphosphate) is considered as the energy currency of the cell as it stores energy in the cell. It is an example of chemical potential energy because energy is stored in the high energy containing phosphoanhydride bond (between phosphate molecules in the ATP).

7 0

3 years ago

Of rational function 1 3. + 3 < 0 3x-1 nctions.

pshichka [43]

Answer:

I didn't understand questions properly. Sorry

4 0

3 years ago

PLEASE HELP!!

sp2606 [1]

Inbox me for the answer

6 0

3 years ago

What is the composition, in atom percent, of an alloy that consists of a) 5.5 wt% Pb and b) 94.5 wt% of Sn? Assume that the atom

Anastaziya [24]

Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

Explanation :

First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.

As, 207.2 g of lead contains $6.022\times 10^{23}$ atoms

So, 5.5 g of lead contains $\frac{5.5}{207.2}\times 6.022\times 10^{23}=1.59\times 10^{22}$ atoms

and,

As, 118.71 g of lead contains $6.022\times 10^{23}$ atoms

So, 94.5 g of lead contains $\frac{94.5}{118.71}\times 6.022\times 10^{23}=4.79\times 10^{23}$ atoms

Now we have to calculate the percent composition of Pb and Sn in atom.

$\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%$

and,

$\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100$

$\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%$

Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.

6 0

3 years ago