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LekaFEV [45]
3 years ago
6

How many atoms are in 44 grams of sulfur?

Chemistry
1 answer:
horrorfan [7]3 years ago
3 0

Answer:

Explanation:

The Avagadro constant = 6.022 x 10²³ denotes the no of molecules in one mole of the substance

Regarding Sulphur Dioxide, the molar mass is 64.

Hence 44 g means 44/64 mole of SO2

So no of molecules in 44g of SO2 = 6.022 x 10²³ x 44/64

On simplification,

11/16 x 6.022 x 10²³ molecules are present in 44g of SO2

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A pure substance that is present before a reaction but not after <br> Super Confused
never [62]

Explanation:

Pure subsance is a substance that is made up of only one type of particle - each piece is the same throughout.

Being present before the reaction but not after means it's no the same (it couldve evaporated)

4 0
3 years ago
The compound 2,2-dimethylpentane has several structural isomers. how many of the isomers are straight-chained?
neonofarm [45]
The answer Is (1)...Straight Isomer when you put them together.





Hope that helps!!!
8 0
3 years ago
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How much ch2o is needed to prepare 445 ml of a 2.65 m solution of ch2o?
worty [1.4K]

Answer: 35.4 grams

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

Molality = 2.65

n= moles of solute =?

 V_s = volume of solution in ml = 445 ml

Putting in the values we get:

2.65=\frac{n\times 1000}{445ml}

n=1.18

Mass of solute in g=moles\times {\text {molar mass}}=1.18mol\times 30.02g/mol=35.4g

Thus 35.4 grams of CH_2O is needed to prepare 445 ml of a 2.65 m solution of CH_2O.

8 0
3 years ago
Which of the following elements does not form hydride by direct heating with
ozzi
I believe the answer is A.

Hope this helps! ^^
4 0
3 years ago
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Determine the molarity of a solution formed by dissolving 97.7 g libr in enough water to yield 750.0 ml of solution.
rewona [7]

Answer:

1.5 M.

Explanation:

  • Molarity (M) is defined as the no. of moles of solute dissolved in a 1.0 L of the solution.

<em>M = (no. of moles of LiBr)/(Volume of the solution (L).</em>

<em></em>

∵ no. of moles of LiBr = (mass/molar mass) of LiBr = (97.7 g)/(86.845 g/mol) = 1.125 mol.

Volume of the solution = 750.0 mL = 0.75 L.

∴ M = (no. of moles of luminol)/(Volume of the solution (L) = (1.125 mol)/(0.75 L) = 1.5 M.

3 0
4 years ago
Read 2 more answers
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