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3 years ago

How many atoms are in 44 grams of sulfur?

Chemistry

1 answer:

horrorfan [7]3 years ago

3 0

Answer:

Explanation:

The Avagadro constant = 6.022 x 10²³ denotes the no of molecules in one mole of the substance

Regarding Sulphur Dioxide, the molar mass is 64.

Hence 44 g means 44/64 mole of SO2

So no of molecules in 44g of SO2 = 6.022 x 10²³ x 44/64

On simplification,

11/16 x 6.022 x 10²³ molecules are present in 44g of SO2

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In Thomson’s model of the atom , what parts of the atom were in motion

trasher [3.6K]

Answer:

The electrons where in motion

4 0

4 years ago

If 16.4 grams of calcium nitrate is heated as shown in the reaction:

vfiekz [6]

Answer:

7.2

Explanation:

you first have to find the number of moles of nitrogen dioxide by using the number of moles for calcium nitrate and the mole to mole ratios

number of moles of calcium nitrate=mass/mm

=16.4/102

=0.16g/mol

then you use the mole to mole ratios

2 : 4

0.16: x

2x/2=0.64/2

x=0.32g/moles of nitrogen dioxide

then you use the formula for the volume

v=22.4n

=22.4×0.32

=7.2

I hope this helps

4 0

3 years ago

A freezer compartment is covered with a 2-mm-thick layer of frost at the time it malfunctions. If the compartment is in ambient

ruslelena [56]

Answer:

The time required to melt the frost is 3.25 hours.

Explanation:

The time required to melt the frost dependes on the latent heat of the frost and the amount of heat it is transfered by convection to the air .

The heat transferred per unit area can be expressed as:

$q=h_c*A*\Delta T\\\\q/A=h_c*\Delta T$

being hc the convective heat transfer coefficient (2 Wm^-2K^-1) and ΔT the difference of temperature (20-0=20 °C or K).

$q/A=h_c*\Delta T=2\frac{W}{m^2K}*20K=40\frac{W}{m^2}$

If we take 1 m^2 of ice, with 2 mm of thickness, we have this volume

$V=T*A = 0.002 m * 1 m^2=0.002m^3$

The mass of the frost can be estimated as

$M=\rho * V=700\frac{kg}{m^3}*0.002m^3= 1.4 kg$

Then, the amount of heat needed to melt this surface (1 m²) of frost is

$Q=L*M=334\frac{kJ}{kg}*1.4kg= 467.6kJ$

The time needed to melt the frost can be calculated as

$t=\frac{Q}{(q/A)}=\frac{467.6kJ/m2}{40W/m2} = 11.69\frac{kJ}{W}*\frac{1W*s}{1J}*\frac{1000J}{1kJ}= 11690s=3.25h$

7 0

3 years ago

Which part of the cell does this illustration represent?

Svetllana [295]

Answer: Mitochondria. The mitochondria contains cristae.

6 0

3 years ago

Read 2 more answers

You have a solution that is 18.5% (v/v) methyl alcohol. If the bottle contains 1.64 L of solution, what is the volume (V) in mil

Juliette [100K]

Answer:

303.4 millimeters

Explanation:

Just multiply 1.64 by 0.185. then convert that answer to millimeters

7 0

3 years ago