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Mrac [35]
3 years ago
12

Which question is the best scientific question?

Chemistry
1 answer:
Mandarinka [93]3 years ago
6 0

<em>Answer</em><em>:</em><em> </em><em>What</em><em> </em><em>does</em><em> </em><em>a</em><em> </em><em>duck</em><em> </em><em>eat</em><em> </em><em>most</em><em> </em><em>often</em><em>?</em>

<em>Option</em><em> </em><em>D</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>best</em><em> </em><em>scientifi</em><em>c</em><em> </em><em>ques</em><em>tion</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps.</em><em>.</em><em>.</em><em>.</em>

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Please match these thanks and have a great day!!! :)) due in 4 minutes
valentina_108 [34]

Answer:

fist one is freezing next two is condensation

Explanation:

6 0
3 years ago
How much sulphur dioxide is produced on complete combustion of 1 kg of coal containing 6.23percent sulphur?
Tresset [83]

Answer:

Approximately 1.24 \times 10^{2}\; \rm g, assuming that all sulfur in that coal was converted to \rm SO_2.

Explanation:

Look up the relative atomic mass of \rm S and \rm O on a modern periodic table:

  • \rm S: 32.06.
  • \rm O: 15.999.

Convert the unit of the mass of coal to grams:

\begin{aligned} & m(\text{coal})= 1\; \rm kg \times \frac{10^{3}\; \rm g}{1\; \rm kg} = 1000\; \rm g\end{aligned}.

Mass of sulfur in that much coal:

m(\text{sulfur}) = 1000\; \rm g \times 6.23\% = 62.3\; \rm g.

The relative atomic mass of sulfur is 32.06. Therefore, the mass of each mole of sulfur atoms would be 32.06\; \rm g. Calculate the number of moles of atoms in that 62.3\; \rm g of sulfur:

\begin{aligned}& n(\text{S})\\&= \frac{m(\mathrm{S})}{M(\mathrm{S})}\\ &= \frac{62.3\; \rm g}{32.06\; \rm g \cdot mol^{-1}} \approx 1.94323\; \rm mol\end{aligned}.

Each \rm SO_2\! molecule contains one sulfur atom. Therefore, assuming that all those (approximately) 1.94323\; \rm mol\! of sulfur atoms were converted to \rm SO_2 molecules through the reaction with \rm O_2, (approximately) 1.94323\; \rm mol of \!\rm SO_2 molecules would be produced.

Calculate the mass of one mole of \rm SO_2 molecules:

\begin{aligned}& M(\mathrm{SO_2})\\ &= 32.06 + 2\times 15.999 \\ &= 64.058\; \rm g \cdot mol^{-1}\end{aligned}.

The mass of that 1.94323\; \rm mol of \rm SO_2 molecules would be:

\begin{aligned}& m(\mathrm{SO_2}) \\ &= n(\mathrm{SO_2}) \cdot M(\mathrm{SO_2}) \\ &\approx 19.4323\; \rm mol \\ &\quad \times 64.058\; \rm g \cdot mol^{-1} \\ &\approx 1.24\times 10^{2}\; \rm g\end{aligned}.

8 0
3 years ago
A certain metal fluoride crystallizes in such a way that the fluoride ions occupy simple cubic lattice sites, while the metal io
Bezzdna [24]

Answer:

MF_2

Explanation:

In a simple cubic lattice lattice, the atoms are present at the eight corners of the cibe.

Since it is mentioned that the fluorine is present at the corners and also 1 corners are shared by 8 unit cells. So, share of atom in one unit cell is:- 8\times \frac{1}{8}=1

Also, the metal, M occupy half of the body centre. A cube has only one body centre. So, share of M in each unit cell:- \frac{1}{2}

Thus, the formula is:-

M_{\frac{1}{2}}F Or simplifying MF_2

3 0
3 years ago
Calculate the temperature change in the water upon complete melting of the ice. Hint: Determine how much heat is absorbed by the
Anvisha [2.4K]

Answer:

The temperature change is 80°C

Explanation:

Heat absorbed by the melting ice (Q) = mL = 312×336 = 104,832 J

∆T = Q/mC = 104,832/312×4.2 = 80°C

4 0
3 years ago
Recessive genes are _____.
AveGali [126]

Answer:

1) represented by a lower case letter
2) always masked by dominant genes

3) only expressed in the absence of a dominant gene

Explanation:

So if I take a black and a yellow marker- and tried drawing the yellow over the black- or the other way around- you'd still only see the black marker. The recessive trait is like the yellow marker. Now if I drew the yellow marker with another yellow marker you would see the yellow. I hope this helps!

8 0
2 years ago
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