Answer:
Power = 15[W]
Explanation:
This problem can be solved using the work definition.
Work is equal to the product of the force by the distance, for this problem we have:
F = force = 30 [N]
d = distance = 30 [m]
w = work = F * d = 30*30 = 900 [J], "units in joules"
The power is defined as the work done in an interval of time.
P = w / t
where:
t = time [s]
therefore
P = w / t
P = 900 / 6
P = 150 [W] "units in watts"
Hi!
The answer would be A. Isobaric Process
<h3>Explanation:</h3>
Isobaric process is a process where the pressure inside a system remains unchanged. In the Pressure Volume graph given, you can see that the pressure (y axis) remains constant with an increasing volume ( x axis). An example of this would be heating a container with a movable piston. Now, the degree of pressure is dependent on the frequency of collisions of particles inside a system on the walls. If this frequency changes, the pressure changes (proportionally). In our example, heating a container with a movable piston results in the particles inside the container to gain kinetic energy and move faster, meaning an increased frequency of collisions (higher pressure), but at the system time the increase in pressure results in the piston being pushed outwards, causing the volume of the container to increase. This results in decreased frequency of collision of the particles with the walls of the container (lesser pressure). This results in the a zero net effect on the pressure.
Hope this helps!
Answer:
Time taken = 10400 s
Explanation:
Given:
Initial speed of the train, 
Final speed of the train, 
Displacement of the train, 
Using Newton's equation of motion,
Now, using Newton's equation of motion for displacement,
Now, plug in the value of 
in the above equation. This gives,
Now, plug in 234000 m for 
, 25 m/s for 
and 20 m/s for 
. Solve for 
.
Therefore, the time taken by the train is 10400 s.
Makes no sense get a better question
Answer: q2 = -0.05286
Explanation:
Given that
Charge q1 = - 0.00325C
Electric force F = 48900N
The electric field strength experienced by the charge will be force per unit charge. That is
E = F/q
Substitute F and q into the formula
E = 48900/0.00325
E = 15046153.85 N/C
The value of the repelled second charge will be achieved by using the formula
E = kq/d^2
Where the value of constant
k = 8.99×10^9Nm^2/C^2
d = 5.62m
Substitutes E, d and k into the formula
15046153.85 = 8.99×10^9q/5.62^2
15046153.85 = 284634186.5q
Make q the subject of formula
q2 = 15046153.85/ 28463416.5
q2 = 0.05286
Since they repelled each other, q2 will be negative. Therefore,
q2 = -0.05286
