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3 years ago

Why is one side of the moon called "the dark side of the moon"?

1 answer:

7 0

' A ' and ' C ' both say the same thing, and both are correct statements. But they're not a reason to call any part of the moon a "dark side". No part of the moon is dark for more than 2 weeks at a time, and the only reason to talk about a "dark side" of it is ignorance.

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An electric field of 100 V/m is directed outward from the plane of a circular area with radius 4.0 cm. If the electric field inc

Flura [38]

Answer:

The magnitude of the magnetic field is $8.9\times10^{-19}\ T$

Explanation:

Given that,

Electric field = 100 V/m

Radius = 4.0 cm

Electric field increase at a rate = 10 V/ms

Radial distance = 10.0 cm

We need to calculate the magnetic field

Using Gauss's law

$\oint{\vec{E}\cdot\vec{dA}}=\phi_{E}$

$\dfrac{dE}{dt}A=\dfrac{d\phi_{E}}{dt}$

$\dfrac{dE}{dt}(\pi r^2)=\dfrac{d\phi_{E}}{dt}$

We need to calculate the $\dfrac{d\phi}{dt}$

$\dfrac{d\phi}{dt}=10\times\pi\times(4.0\times10^{-2})^2$

$\dfrac{d\phi}{dt}=0.0503\ Nm^2/C.s$

According to Ampere Maxwell law

$\oint{\vec{B}\cdot \vec{ds}}=\mu_{0}(I+\epsilon_{0}\dfrac{d\phi_{E}}{dt})$

$\oint{\vec{B}\cdot\vec{ds}}=\mu_{0}I+\mu_{0}\epsilon_{0}\dfrac{d\phi_{E}}{dt})$

Electric field is zero inside the circle.

$\oint{\vec{B}\cdot \vec{ds}}=\mu_{0}\epsilon_{0}\dfrac{d\phi_{E}}{dt})$

$B(2\pi\times10.0\times10^{-2})=4\pi\times10^{-7}\times8.85\times10^{-12}\times0.0503$

$B=\dfrac{4\pi\times10^{-7}\times8.85\times10^{-12}\times0.0503}{2\pi\times10.0\times10^{-2}}$

$B=8.9\times10^{-19}\ T$

Hence, The magnitude of the magnetic field is $8.9\times10^{-19}\ T$

6 0

3 years ago

A model rocket is fired vertically from rest. It has a constant acceleration of 16.4 m/s2 for the first 1.50 s. Then its fuel is

il63 [147K]

Answer:

The force downward acting o the rocket is F=m*g=0.0782kg*9.8m/s^2=0.76636 N

Explanation:

3 0

3 years ago

A 750 kg National Geographic Drone is rising vertically up into the atmosphere at constant speed. The lift force pushing it upwa

Debora [2.8K]

Answer:

a. 0

b. 1.103625 MJ

c. Conserved

d. 1.103625/n MJ where n = The number of forces

Explanation:

The mass of the drone, m = 750 kg

The upward lift force = 125% of the weight of the drone

The time it takes the drone to reach a height of 250 m = 25 seconds

a. The mechanical energy = The kinetic energy + Potential energy

Therefore, given that the drone stars motion from the surface and was initially at rest, the mechanical energy at the surface = 0

b. The mechanical energy at height, h = 150 m, ME₁₅₀ = The potential energy gained = m·g·h

Where;

g = The acceleration due to gravity = 9.81 m/s²

∴ ME₁₅₀ = 750 kg × 9.81 m/s² × 150 m = 1103625 J = 1.103625 MJ

c. The mechanical energy is equivalent to the potential energy of the drone at the 150 m height, therefore, it is conserved

d. The work done by the force = The energy gained

Therefore, where there are <em>n</em> number of forces, the work done by each force = 1.103625/n MJ

5 0

3 years ago

A car weighing 11.1 kN and traveling at 13.4 m/s without negative lift attempts to round an unbanked curve with a radius of 61.0

klasskru [66]

Answer:

Well..

Explanation:

That's impossible. I know because I once weighed 11.1 kN, and I was temporarily immobile. It's probably the same for a car, and therefore it can not be "traveling" anywhere at all.. unless you put the car on an airplane or a boat or something.

8 0

3 years ago

The amplitude of a sound is the A. frequency of the sound. B. magnitude of displacement of a sound pressure wave. C. psychologic

AlladinOne [14]

Answer:

Option B. magnitude of displacement of a sound pressure wave

Explanation:

Amplitude is simply the maximum displacement of a wave from its mean position.

6 0

4 years ago

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