I have to go with True because a Rhombus is a Square.
we can divide the equation on (x+1) and if we have a real solutons (x+1) is a factor
is a factor because the remainder is 0
so the new form of the equation is
The cotangent function is defined as the ratio between cosine and sine of a given angle, i.e.
Since you can't have zero at the denominator, the cotangent function is not defined when the sine is zero.
Let's look at your option:
, so the cotangent is defined here
, so the cotangent is not defined here
, so the cotangent is defined here
, so the cotangent is defined here
It is given that, B ≅ BC and AD ≅ CD
We need BD perpendicular to AC, then only we can say triangles AXB and CXB are congruent using the HL theorem.
If BD perpendicular to AC, means that AB and CB are the hypotenuse of triangles AXB and CXB respectively.
from the given information ABCD is a square
If BD and AC bisect each other then AX = CX
Then only we can immediately possible to prove that triangles AXD and CXD are congruent by SSS congruence theorem
