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Arada [10]
3 years ago
7

Solve the system by substitution. x−5y=−11 −6y=x

Mathematics
1 answer:
antoniya [11.8K]3 years ago
3 0

Answer:

y=x,y=12x+1

y=4x+4,y=6x

y=x+1,y=x+4

Step-by-step explanation:

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What is the constant proportionality in the equation y = 6x?
Lesechka [4]

Answer: the constant of proportionality is x

Step-by-step explanation:

5 0
3 years ago
The formula is: <br><img src="https://tex.z-dn.net/?f=v%20%3D%20%20%5Cfrac%7B4%7D%7B3%7D%5Cpi%20%7Br%7D%5E%7B3%7D%20" id="TexFor
uranmaximum [27]

Answer:

Volume of hemisphere=

<u>\frac{2}{3} \pi   {r}^{3}</u>

<u>Volume</u><u> </u><u>of</u><u> </u><u>sphere</u><u>=</u><u> </u>

<u>\frac{4}{3} \pi {r}^{3}</u>

Step-by-step explanation:

\frac{2}{3}  \times  \frac{22}{7}  \times  {8}^{3}

Using calculator=

1072.761905

Round to the nearest tenth=

1072.8

5 0
3 years ago
P= -24<br>q= 12<br>r= -6<br><br>a. (pxq):(q+r)<br>b. (pxr):(r-q)<br><br>what the answer?​
kolezko [41]

Step-by-step explanation:

a. ( p × q ) ( q + r )

= ( -24 × 12 ) ( 12 + -6 )

= 288 × 18

= 5184

b. ( p × r ) ( r - q )

= ( -24 × -6 ) ( -6 - 12 )

= ( 144 ) ( -18 )

= -2592

5 0
3 years ago
Lim x-1 x2 - 1/ sin(x-2)
balu736 [363]

Answer:

           \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0

Explanation:

Assuming the correct expression is to find the following limit:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}

Use the property the limit of the quotient is the quotient of the limits:

         \lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}

Evaluate the numerator:

          \frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}

Evaluate the denominator:

  • Since         \lim_{x \to1}sin(x-2)\neq 0

                  \frac{0}{\lim_{x \to1}sin(x-2)}=0

4 0
3 years ago
HELP HELP HELP HELP HELP HELP
denis-greek [22]

Answer:

1 question : 0.89 I think.

7 0
3 years ago
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