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Allushta [10]
3 years ago
10

Question 2 (1.5 points)

Chemistry
1 answer:
Irina18 [472]3 years ago
7 0

Answer

The answer is: a hidden element, such as a valuable collectible item, or novelty item

Explanation:

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The distance from the sun to earth would be ______.
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C- more than one light year or B-exactly one light year
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13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the
wariber [46]

Answer:

13. 2.60 L.

14. 2.40 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If n and T are constant, and have different values of P and V:

(P₁V₁) = (P₂V₂)

<em>13. A gas occupies 4.31 liters at a pressure of 0.755 atm. Determine the volume if the  pressure  is increased to 1.25 atm.</em>

P₁ = 0.755 atm, V₁ = 4.31 L.

P₂= 1.25 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (0.755 atm)(4.31 L)/(1.25 atm) = 2.60 L.

<em>14. 600.0 mL of a gas is at a pressure of 8.00 atm. What is the volume of the gas at 2.00  at m.</em>

P₁ = 8.0 atm, V₁ = 600.0 mL.

P₂= 2.0 atm, V₂ = ??? L.

∴ V₂ = (P₁V₁)/(P₂) = (8.0 atm)(600.0 mL)/(2.0 atm) = 2400/0 mL = 2.40 L.

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A balloon moves vertically upward at
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6 0
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If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
irinina [24]

Answer:

4.13 g

Explanation:

Data Given:

Amount of CO₂ Produced = 15 g

Amount of Oxygen = 11 g

Amount of Carbon used = ?

Solution:

Suppose Carbon dioxide (CO₂) is formed by the reaction of carbon and oxygen then the reaction will be as below

                            C   +   O₂    -------------> CO₂

                          1 mol    1 mol                  1 mol

we come to know from the above reaction that

1 mole of carbon react with 1 mole of oxygen to produce 1 mol of carbon dioxide.

molar mass of C = 12 g/mol

molar mass of O₂ = 32 g/mol

molar mass of CO₂ = 12 + 2(16) = 44 g/mol

if we represent mole in grams then

           C               +                        O₂                     ------------->        CO                 1 mol (12 g/mol)                      1 mol (32 g/mol)                      1 mol (44 g/mol)

                   

              C   +   O₂    -------------> CO₂

            12 g       32 g                   44 g

So,

we come to know that 32 g of Oxygen combine with 12 g  of oxygen produce 44 g CO₂

So now how much of Carbon will be combine with 11 g of oxygen

apply unity formula

                32 g of  O₂ ≅ 12 g of  C

                  11 g of O₂  ≅  g of  C

by doing cross multiplication

           g of C = 12 g x 11 g / 32 g

           g of C = 132 g / 32 g

           g of C = 4.13 g

So,

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

to check this answer

we use the above information

                     12 g of  C ≅ 44 g of CO₂

                     4.13 g of C ≅  g of  CO₂

by doing cross multiplication

                    g of  CO₂ = 44 g x 4.13 g / 12 g

                    g of CO₂ = 15g

So it is confirmed that

4.13 g of carbon will consume to produce 15 g of Carbon dioxide.

4 0
3 years ago
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