Answer:
I = 0.09[amp] or 90 [milliamps]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
Now, we replace the values of the first current into the equation
V = 180*10^-3 * R
V = 0.18*R (1)
Then we have that the resistance is doubled so we have this new equation:
V = I*(2R) (2)
The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.
V = V
0.18*R = I*2*R
I = 0.09[amp] or 90 [milliamps]
Answer:
Use of telemetry and radar astronomy
Explanation:
An astronomical Unit (AU) is a unit of measuring distances in outer space, which is based on the approximate distance between the earth and the Sun.
After several years of trying to approximate the distance between the Sun and the Earth using several methods based on geometry and some other calculations, advancements in technology made available the presence of special motoring equipment, which can be placed in outer space to remotely monitor and measure the position of the sun.
The use of direct radar measurements to the sun (radar astronomy) have also made the determination of the AU more accurate.
A standard radar pulse of known speed is sent to the Sun, and the time with which it takes to return is measured, once this is recorded, the distance between the Earth and the Sun can be calculated using
distance = speed X time.
However, most of these means have to be corrected for parallax errors
Answer:
221.17 kJ
Explanation: Note the heat of vaporization is in kJ/mol,then to determine the number of moles of water: divide the mass by 18. Then multiply the number of moles by the molar heat of vaporization of water.
N = 97.6 ÷ 18
Q=molar heat *moles
Q = (40.79) * (97.6 ÷ 18)
This is approximately 221.17 kJ
P=IV, where P is power, I is resistance, and V is voltage. Plug in and solve:
P=400(20)
P=8000W
Hope this helps!!
Answer:
Explanation:
In this question we have given
we have to find
We know that
optical path difference for bright fringe is given as
Here,
n is order of fringe
and optical path difference for dark fringe is given as
since the light with wavelength 
produces its third-order bright fringe at the same place where the light with wavelength 
produces its fourth dark fringe
it means
optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe
Therefore,
...............(1)
Put value of in equation (1)
