The distance for any rectilinear motion at constant acceleration is:
d = v₀t + 0.5at²
where
v₀ is the initial velocity
So, if v₀ = 6v, and it stopped to 0 m/s, then the acceleration is equal to:
a = (0 - 6v)/t = -6v/t
Thus,
d = (6v)(t) + (0.5)(-6v/t)(t²)
d = 6vt - 3t
<span>d = 3t(2v - 1)</span>
A ball would be something that floats in warter
To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

Here,
= Wavelength
= Angle when occurs the interference point of destructive interference
Our values are given as,


Using the previous expression we have,





Therefore the distance between the two openings is 
Answer:
about 186,000 miles per second
Explanation:
so your closest bet is probably 175 miles per second