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lilavasa [31]
3 years ago
8

The gravitational force between two objects is 2400 N. What will be the gravitational force between the objects if the mass of o

ne object is doubled?
Physics
1 answer:
Sindrei [870]3 years ago
7 0

Answer:

4800N

Explanation:

F=GmM/r^2

F=infinite m

F=2F

=2(2400N)

=4800N

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Suppose a sound wave and an electromagnetic wave have the same frequency. Which has the longer wavelength?
ivann1987 [24]

Answer:

Electromagnetic wave has longer wavelength.

Explanation:

The velocity (v) of a wave is the product between frequency (f) and wavelength (λ):

v=\lambda f (1)

Electromagnetic waves travel on air near the velocity of light 299792458 \frac{m}{s}, and sound waves travel on air at approximately 343,2 \frac{m}{s}, so if the frequency is equal for both, and the velocity is directly proportional to wavelength as shown in (1) then higher velocities imply higher wavelengths, that is, electromagnetic wave has longer wavelength.

3 0
3 years ago
Using a refracting telescope, you observe the planet Mars when it is 2.11 × 10 11 m 2.11×1011 m from Earth. The diameter of the
Norma-Jean [14]

Answer:

y = 150 Km

Explanation:

given,                                                      

Distance of the planet Mars from earth D = 2.11 × 10¹¹ m          

The diameter of the telescope's objective lens d = 0.949 m      

The wavelength of light λ = 553 nm            

                                        = 553 x 10⁻⁹ m            

resolution of the telescope = ?                          

     y = \dfrac{1.22\lambda\ D}{d}          

     y = \dfrac{1.22\times 553\times 10^{-9}\times 2.11 \times 10^{11}}{0.949}                                          

           y = 150003 m                          

          y = 150 Km                          

the minimum feature size is equal to y = 150 Km

8 0
3 years ago
I will give brainliest to person who answers correctly
Mamont248 [21]
I think the first one
6 0
2 years ago
An inexperienced catcher catches a 126 km/h fastball of mass 160 g within 1.36 ms, whereas an experienced catcher slightly retra
Firdavs [7]

Answer:

4117.65 N

Explanation:

Speed of ball, u = 126 km/h = 35 m/s

Mass of ball, m = 160 g = 0.16 kg

Time interval, t = 1.36 ms = 0.00136 s

We can calculate the force as a measure of the momentum of the ball:

F = P/t

Momentum, P, is given as:

P = mv

Therefore:

F = (mv) / t

F = (0.16 * 35) / (0.00136)

F = 4117.65 N

The force imparted to the two glove d hands of the inexperienced catcher is 4117.65 N.

6 0
3 years ago
Your friend is writing a crime drama and wants your input on the credibility of a plot point. A burglar is running as fast as he
pickupchik [31]

Answer:

No, he will not make it.

Explanation:

The equations for  the position of the burglar during the jump are as follows:

r = (x0 + v0x · t, y0 + 1/2 · g · t²)

Where:

r = position vector of the burglar at time t

x0 = initial horizontal position

v0x = initial horizontal velocity

t = time

y0 = initial vertical position

g = acceleration due to gravity

When the burglar reaches the rooftop of the lower building, his vector position will be "r final" (see the attached figure), taking as the center of the frame of reference the jumping point. As you can see in the figure, the vector "r final" is:

r final = (8.0 m, -3.0 m)

The x-component of the vector "r final" can be calculated using the equation of the vector r, above:

x = x0 + v0x · t      (x0 = 0)

8.0 m =  v0x · t  

In the same way with the y-component:

y = y0 + 1/2 · g · t²          (y0 = 0)

-3.0 m =  -1/2 · 9.8 m/s² · t²

We can calculate the horizontal velocity since we know that the burglar can run 100 m in 10,8 s. Then, his velocity will be:

v = x/t

Where: v = velocity, x = position, t = time.

v = 100 m / 10.8 s = 9.26 m/s

Now, we can calculate the time of flight of the burglar with the equation for the x-component of the vector position.

8.0 m =  v0x · t

8.0 m = 9.26 m/s · t

t = 8.0 m / 9.26 m/s

t = 0.86 s

Now, let´s see what is the y-component of the vector position at that time:

y = 1/2 · g · t²

y = 1/2 · (-9.8 m/s²) · (0.86 s)²

y = -3.62 m

See in the figure the vector "r real" that will be the position of the burglar if he jumps running at that velocity. His position will be r = (8.0m, -3.62 m). He will miss the edge of the other roof by 0.62 m.

5 0
3 years ago
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