Answer:
g = 1.11x10⁻⁵Ω.
Explanation:
The membrane conductance (g) can be calculated by dividing membrane current (I) through the driving force (Vm - E) as follows:
![g_{ion} = \frac{I_{ion}}{V_{m} - E_{ion}}](https://tex.z-dn.net/?f=%20g_%7Bion%7D%20%3D%20%5Cfrac%7BI_%7Bion%7D%7D%7BV_%7Bm%7D%20-%20E_%7Bion%7D%7D%20)
<em>where Vm: is the membrane potential and </em>
<em>: is the equilibrium potential for the ion or reversal potential. </em>
The equilibrium potential for the ion can be calculated using the Nernst equation:
<em>where R: is the gas constant = 8.314 J/K*mol, F: is the Faraday constant = 96500 C/mol, T: is the temperature (K), z: is the ion's charge, [ion]out and [ion]ins: is the concentration of the ion outside and inside, respectively. </em>
Now, we can calculate the membrane conductance (g) using equation (1):
![g_{ion} = \frac{I_{ion}}{V_{m} - E_{ion}} = \frac{-318*10^{-9} A}{20*10^{-3} V - 48.78*10^{-3} V} = 1.11*10^{-5} \Omega](https://tex.z-dn.net/?f=%20g_%7Bion%7D%20%3D%20%5Cfrac%7BI_%7Bion%7D%7D%7BV_%7Bm%7D%20-%20E_%7Bion%7D%7D%20%3D%20%5Cfrac%7B-318%2A10%5E%7B-9%7D%20A%7D%7B20%2A10%5E%7B-3%7D%20V%20-%2048.78%2A10%5E%7B-3%7D%20V%7D%20%3D%201.11%2A10%5E%7B-5%7D%20%5COmega%20)
Therefore, the membrane conductance is 1.11x10⁻⁵Ω.
I hope it helps you!
gold density = 19.3 g/cm³
mass = 16.5 kg = 16.5 x 10³ g
volume = 954 ml
gold density based on the experiments:
ρ = 16.5 x 10³ g / 954 ml(cm³) = 17.296 g/cm³ ( not of pure gold)
Answer:
k
Explanation:
They must obey the Law of Conservation of Mass that states that matter cannot be created or destroyed, it is conserved. Atoms are never lost or gained in chemical reactions, they are rearranged. The mass of the reactants must equal the mass of the products.
Answer: Lithium ( 3),Calcium (20),Copper (29),Strontium (38),Potassium (19),Sodium (11)
Explanation: