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Papessa [141]
2 years ago
6

Where is the Oort cloud located

Chemistry
1 answer:
chubhunter [2.5K]2 years ago
3 0

Answer:

If the Oort cloud exists which it most likely does it would be C

Explanation:

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A 99.8 mL sample of a solution that is 12.0% KI by mass (d: 1.093 g/mL) is added to 96.7 mL of another solution that is 14.0% Pb
andre [41]

Answer:

m_{PbI_2}=18.2gPbI_2

Explanation:

Hello,

In this case, we write the reaction again:

Pb(NO_3)_2(aq) + 2 KI(aq)\rightarrow PbI_2(s) + 2 KNO_3(aq)

In such a way, the first thing we do is to compute the reacting moles of lead (II) nitrate and potassium iodide, by using the concentration, volumes, densities and molar masses, 331.2 g/mol and 166.0 g/mol respectively:

n_{Pb(NO_3)_2}=\frac{0.14gPb(NO_3)_2}{1g\ sln}*\frac{1molPb(NO_3)_2}{331.2gPb(NO_3)_2}  *\frac{1.134g\ sln}{1mL\ sln} *96.7mL\ sln\\\\n_{Pb(NO_3)_2}=0.04635molPb(NO_3)_2\\\\n_{KI}=\frac{0.12gKI}{1g\ sln}*\frac{1molKI}{166.0gKI}  *\frac{1.093g\ sln}{1mL\ sln} *99.8mL\ sln\\\\n_{KI}=0.07885molKI

Next, as lead (II) nitrate and potassium iodide are in a 1:2 molar ratio, 0.04635 mol of lead (II) nitrate will completely react with the following moles of potassium nitrate:

0.04635molPb(NO_3)_2*\frac{2molKI}{1molPb(NO_3)_2} =0.0927molKI

But we only have 0.07885 moles, for that reason KI is the limiting reactant, so we compute the yielded grams of lead (II) iodide, whose molar mass is 461.01 g/mol, by using their 2:1 molar ratio:

m_{PbI_2}=0.07885molKI*\frac{1molPbI_2}{2molKI} *\frac{461.01gPbI_2}{1molPbI_2} \\\\m_{PbI_2}=18.2gPbI_2

Best regards.

5 0
3 years ago
Read 2 more answers
What type of energy is stored in the earths crust and produces earthquakes
Svetradugi [14.3K]
A rapid release of stored up energy 
8 0
3 years ago
Read 2 more answers
. How many milliliters of 0.20 M HCl are needed to exactly neutralize 40. milliliters of 0.40 M KOH
Anuta_ua [19.1K]

Answer:

V_{HCl}=80mL

Explanation:

Hello,

In this case, for the given reactants we identify the following chemical reaction:

KOH+HCl\rightarrow KCl+H_2O

Thus, we evidence a 1:1 molar ratio between KOH and HCl, therefore, for the complete neutralization we have equal number of moles, that in terms of molarities and volumes become:

n_{HCl}=n_{KOH}\\\\M_{HCl}V_{HCl}=M_{KOH}V_{KOH}

Hence, we compute the volume of HCl as shown below:

V_{HCl}=\frac{M_{KOH}V_{KOH}}{M_{HCl}} =\frac{0.40M*40mL}{0.20M} \\\\V_{HCl}=80mL

Best regards.

5 0
3 years ago
Uranium-238 (U-238) decays into lead-206 (Pb-206). Which of the following is a true statement?
Doss [256]
C is the correct answer
4 0
3 years ago
The main purpose of following the course of a reaction by TLC is to: Group of answer choices Determine if all the starting mater
kakasveta [241]

Determine if all the starting material is converted to the product.

<h3>What is TLC?</h3>

Because it can provide immediate and important information about a sample's purity and whether or not a reaction is still ongoing, TLC is a common technique in the organic chemistry lab. A TLC plate can be finished in less than 5 minutes when low polarity solvents are used.

<h3>Uses of TLC:-</h3>

TLC is a chromatographic method used to separate mixtures that are not volatile.

Thin-layer chromatography can be used to:-

  • Assess a substance's purity.
  • Identify the compounds present in a particular combination.
  • Track the development of a reaction.

Learn more about TLC here:-

brainly.com/question/14393140

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7 0
2 years ago
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