Answer:
The velocity of the Mr. miles is 17.14 m/s.
Explanation:
It is given that,
Mr. Miles zips down a water-slide starting at 15 m vertical distance up the scaffolding, h = 15 m
We need to find the velocity of the Mr. Miles at the bottom of the slide. It is a case of conservation of energy which states that the total energy of the system remains conserved. Let v is the velocity of the Mr. miles. So,
g is the acceleration due to gravity
v = 17.14 m/s
So, the velocity of the Mr. miles is 17.14 m/s. Hence, this is the required solution.
Hey there!
In this case, it is possible to solve this problem by using the widely-known steam tables which show that at 90 °C, the pressure that produces a vapor-liquid mixture at equilibrium is about 70.183 kPa (Cengel, Thermodynamics 5th edition).
Moreover, for the calculation of the volume, it is necessary to calculate the volume of the vapor-liquid mixture, given the quality (x) it has:
Thus, since 8 kg correspond to liquid water, 2 kg must correspond to steam, so that the quality turns out:
Now, at this temperature and pressure, the volume of a saturated vapor is 2.3593 m³/kg whereas that of the saturated liquid is 0.001036 m³/kg and therefore, the volume of the mixture is:
This means that the volume of the container will be:
Regards!
Rod is 450mm and disk has a radius of 75mm So there is a pin holding the assembly upwards which is when Θ=0 and at the pin there is a torsional spring with constant of k=20N m/rad. One end of the rod is attached to the pin and the other is attached to the disk.
Answer:
58.32 N
Explanation:
Area of a circle = 
where r is the radius of the circle.
The cylinder has a radius of 0.02 m, its area is;
=
= 
x 
= x 0.0004
= 1.2571 x 
Area of the cylinder is 0.0013 
.
The safety valve has a radius of 0.0075 m, its area is;
=
= x 
= x 5.625 x 
= 1.7679 x 
Area of the valve is 0.00018 .
From Hooke's law, the force on the safety valve can be determined by;
F = ke
= 950 x 0.0085
= 8.075 N
Minimum force, 
, required can be determined by;
= 
= 
= 
= 58.32
The minimum force that must be exerted on the piston is 58.32 N.
