Mole fraction for silver= 0.2317643/0.3079193
= 0.7526787
Mole fraction for gold=0.076155/0.3079193
=0.2473212
What is Molar Fraction?
The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It serves as a means of indicating how concentrated a solution is.
It is a unit of concentration, defined as the product of the moles of a component and the moles of the entire solution. When all the parts of a solution are summed up, their mole fraction equals 1.
molar mass of silver = 107.8682g/mol
Molar mass of gold= 196.96657g/mol
Therefore mole = mass/molar mass
For silver: 25g/107.8682g/mol = 0.2317643mol
For gold: 15g/196.96657g/mol= 0.076155mol
Total number of mole= 0.2317643+0.076155
= 0.30791193mol
Mole fraction for silver= 0.2317643/0.3079193
= 0.7526787
Mole fraction for gold=0.076155/0.3079193
=0.2473212
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Answer:
Explanation:
Given that:
Pressure = 791 mmHg
Temperature = 20.0°C
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (20 + 273.15) K = 293.15 K
T = 293.15 K
Volume = 100 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 62.3637 L.mmHg/K.mol
Applying the equation as:
791 mmHg × 1.14 L = n × 62.3637 L.mmHg/K.mol × 293.15 K
⇒n of 
produced = 0.0493 moles
According to the reaction:-
1 mole of carbon dioxide is produced 1 mole of calcium carbonate reacts
0.0493 mole of carbon dioxide is produced 0.0493 mole of calcium carbonate reacts
Moles of calcium carbonate reacted = 0.0493 moles
Molar mass of 
= 100.0869 g/mol
The formula for the calculation of moles is shown below:
Thus,
Impure sample mass = 5.28 g
Percent mass is percentage by the mass of the compound present in the sample.
Answer: How many grams are in 2.5 moles of N2?
Explanation: 1 mole is equal to 1 moles N2, or 28.0134 grams.
One mole of N2 molecules would have a mass of 2 X 14.01 g = 28.02 g.
