Answer:
78.4 KN/m
Explanation:
Given
mass of person 'm' =80 kg
car dips about i.e spring stretched 'x'= 1 cm => 0.01m
acceleration due to gravity 'g'= 9.8 m/s^2
as we know that,in order to find approximate spring constant we use Hooke's Law i.e F=kx
where,
F = the force needed
x= distance the spring is stretched or compressed beyond its natural length
k= constant of proportionality called the spring constant.
F=kx ---> (since f=mg)
mg=kx
k=(mg)/x
k=(80 x 9.8)/ 0.01
k=78.4x
k=78.4 KN/m
You traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
<u>Given the following data:</u>
We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find the distance traveled, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
Where:
Substituting the parameters into the formula, we have;
<em>Distance, S</em><em> = </em><em>620.075 meters.</em>
Therefore, you traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
Read more: brainly.com/question/8898885