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Svetradugi [14.3K]
3 years ago
11

Acceleration occurs when an object _____. Select all that apply.

Physics
2 answers:
fomenos3 years ago
3 0

Answer:

speeds up, turns a corner at constant speed, and slows down.

Explanation:

Acceleration occurs anytime an object's speed increases or decreases, or it changes direction.

Aleksandr-060686 [28]3 years ago
3 0
Answer: Goes in a straight line at a constant speed
Speeds up
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While it’s impossible to design a perpetual motion machine, that is, a machine that keeps moving forever, come up with ways to k
TEA [102]
It would be hard so many factors play a role in this angle kinetic potential energy gravity positioning height weight etc.to keep something as described moving as long as possible you'd have to build it heavily enough to balance out the momentum at each climax of the swing to balance with the gravitational pull of the earth core.I'd use a material such as copper for the variable.Also the weight distribution on the variables base plays a role.Take all the into account and experiment for a while!maybe one day you could find the right proportions in every role for kinetic potential gravitational momentum and weight to keep it going forever. As said alotta factors play a huge role in this experiment  <span />
3 0
3 years ago
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A 19.0-g bullet embeds itself in a 8.0-kg wooden block, which rests on a horizontal frictionless surface and is attached to a ho
Anton [14]

Answer:

d) 700 m/s

Explanation:

if k is the force constant and x is the maximum compression distance, then:

the potential energy the spring can acquire is given by:

U = 1/2×k×(x^2)

and, the kinetic energy system is given by:

K = 1/2×m×(v^2)

if Ki is the initial kinetic energy of the system, Ui is the initial kinetic energy of the system and Kf and Uf are final kinetic and potential energy respectively then, According to energy conservation:

initial energy  = final energy

            Ki +Ui = Kf +Uf

Ui = 0 J and Kf = 0J

                  Ki = Uf

   1/2×m×(v^2) = 1/2×k×(x^2)

         m×(v^2) = k×(x^2)

                v^2 = k×(x^2)/m

                       = (500)×((21×10^-2)^2)/(19×10^-3 + 8)

                       = 2.75

                    v = 1.66 m/s

the v is the final velocity of the bullet block system, if m1 is the mass of bullet and M is the mass of the block and v1 is the initial velocity of the bullet while V is the initial velocity of the block, then by conservation linear momentum:

m1×v1 + M×V = v×(m1 + M) but V = 0 because the block is stationary, initially.

          m1×v1 = v×(m1 + M)

                v1 =  v×(m + M)/(m1)

                    =  (1.66)×(19×10^-3 + 8)/(19×10^-3)

                    = 699.86 m/s

                    ≈ 700 m/s

Therefore, the velocity of the bullet just before it hits the block is 700 m/s.  

5 0
3 years ago
What is measured by the amount of time a muscle group can sustain a contraction? A. Muscular endurance B. Muscular strength C. C
PtichkaEL [24]

Answer:

A. Muscular endurance

Explanation:

Muscular endurance is measured by the amount of time a muscle group can sustain a contraction.

5 0
3 years ago
Answer all three parts and show work.
sleet_krkn [62]

The distance for both Parts A and B are given in the question.

A balloon drifts 140m toward the west in 45s.

The wind suddenly changes and the balloon flies 90m toward the east in the next 25s.

To find the total distance, we can just add.

140 + 90 = 230m

Best of Luck!

5 0
3 years ago
WILL GIVE BRAINIEST!!!
Nonamiya [84]

I think it would be D...

3 0
3 years ago
Read 2 more answers
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