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3 years ago

Which of the following would be produced when two or more different atoms bond chemically?

Chemistry

1 answer:

ExtremeBDS [4]3 years ago

7 0

Answer:

When two or more atoms chemically bond with each other, the resultant chemical structure is a molecule. The familiar water molecule, H2O, consists of two hydrogen atoms and one oxygen atom; these bond together to form water, irdk but it's either C or D

Explanation:

hope this helps have a good rest of your day :) ❤

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Answer:

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2 years ago

Match each type of reaction to its amount of potential energy. (PLEASE HELP )

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3 years ago

A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas

swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $T_1$ = $K_1$

$K_2$ = rate constant at $T_2$ = $3K_1$

$Ea$ = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]$

$T_2=392.462K$

Therefore, the temperature will be, 392.462 K

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3 years ago

Given: C + O2 → CO2 Bond Bond Energy (kJ/mol) C=O 799 O=O 494 Calculate the enthalpy change for the chemical reaction. The chang

aliya0001 [1]

Answer:

-1104 kJ/mol

Explanation:

The change in the enthalpy of a reaction is equal to the difference between: the sum of the enthalpy changes of the bonds broken and the sum of the enthalpy changes of the bonds formed.

The bonds broken correspond to the cleavage of bonds of the reactants, the bonds formed correspond to the bonds of the products:

we only break oxygen O=O bond, since carbon is not bonded to anything;
we form two C=O bonds in carbon dioxide.

Therefore, the enthalpy change is calculated by:

$\Delta H^o = 1 mol\cdot 494 kJ/mol - 2 mol\cdot 799 kJ/mol = -1104 kJ/mol$

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3 years ago

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Answer:

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Explanation:

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3 years ago