Answer:
74.6 g
Explanation:
The computation of the number of grams produced at the time when 32.0 grams of C react is shown below:
As we know that
But before that we need to find out the moles of c i.e carbon which is
= 2.66 mol
As we know that
1 mol of C produces 1 mol of CO
So, for 2.66 mol, the mass of CO is
= 74.6 g
Basically we applied the above equation so that we can reach to the answer
Answer:
added water = 171 ml
Explanation:
Assuming volumes are additive, the rule that we will use to solve this question is:
M1V1 = M2V2
where:
M1 is the initial concentration = 0.4 m
V1 is the initial volume = 57 ml
M2 is the final concentration = 0.1 m
V2 is the final volume that we want to calculate
Substitute with the given in the above equation to get V2 as follows:
M1V1 = M2V2
(0.4)(57) = (0.1)V2
22.8 = 0.1V2
V2 = 228 ml
Now, the final volume is equal to the initial volume plus the amount of added water. So, to get the amount of added water, we will subtract the initial volume from the final volume as follows:
V2 = V1 + added water
228 = 57 + added water
added water = 228 - 57 = 171 ml
Hope this helps :)