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3 years ago

A

Physics

1 answer:

zhuklara [117]3 years ago

7 0

Hello! For this excersice let's applicate the formula:

$\boxed{\boxed{d=vt}}$

Data:

d = Distance = 150 m

v = Velocity = ¿?

t = Time = 0,9 s

Now, let's replace according the formula:

$\boxed{150 \ m = v * 0,9 \ s}$

Clear v:

$\boxed{\dfrac{150 \ m}{0,9 \ s} = v}$

Resolving:

$\boxed{166,67 \ m/s = v}$

The velocity is <u>166,67 meters per second.</u>

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$(56*9.81*1400)-E_{friction}=\frac{1}{2}*56*(5.6)^{2}\\769104 -E_{friction}= 878.08 \\E_{friction}=769104-878.08\\E_{friction}=768226[J] = 768.23 [kJ]$

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