Please help me i have this due tommorrow!!!
1 answer:
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Answer:
(I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.
Explanation:
Given that,
Initial spinning = 50.0 rad/s
Time = 20.0
Distance = 2.5 m
Mass of pole = 4 kg
Angle = 60°
We need to calculate the angular acceleration
Using formula of angular velocity
The angular acceleration is -2.5 rad/s²
We need to calculate the number of revolution
Using angular equation of motion
Put the value into the formula
The number of revolution is 500 rad.
(II). We need to calculate the torque
Using formula of torque
Put the value into the formula
Hence, (I). The angular acceleration and number of revolution are -2.5 rad/s² and 500 rad.
(II). The torque is 84.87 N-m.