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Dmitry_Shevchenko [17]
3 years ago
10

B. MgF2 Name the compound

Chemistry
1 answer:
algol [13]3 years ago
5 0

Answer:

Magnesium Difluoride

Explanation:

Mg = magnesium

F = fluoride

F2 = difluoride (prefix "di" indicates 2)

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Many monatomic ions are found in seawater, including the ions formed from the following list of elements. Write the Lewis symbol
77julia77 [94]

Answer:

The Lewis structures are in image attached.

Explanation:

Lewis symbol is a representation of an element symbol along with its valence electrons around it in the form of dot(s).

Mono-atomic ions formed from the following :

(a) Cl

Chlorine's atomic number is 17 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet

Cl=1s^22s^22p^63s^23p^5

Cl^-=1s^22s^22p^63s^23p^6

(b) Na

Sodium's atomic number is 11 in which only 1 electrons are present in its valence shell .So in order to gain noble gas stability it will loose 1 electron to completes its octet. In the Lewis symbol no dot shown as sodium has lost its 1 electron.

Na=1s^22s^23p^63s^1

Na^+=1s^22s^23p^63s^0

(c) Mg

Magnesium's atomic number is 12 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electrons to completes its octet.

In the Lewis symbol no dot shown as magnesium has lost its 2 electrons.

Mg=1s^22s^23p^63s^2

Mg^{2+}=1s^22s^23p^63s^0

(d)Ca

Calcium's atomic number is 20 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 2 electron.

Ca= 1s^22s^22p^63s^23p^64s^2

Ca^{2+}=1s^22s^23p^6^23p^64s^0

(e) K

Potassium's atomic number is 19 in which only 1 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 1 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 1 electron.

K= 1s^22s^22p^63s^23p^64s^1

K^{+}=1s^22s^23p^6^23p^64s^0

(f) Br

Bromine's atomic number is 35 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet

Br=1s^22s^22p^63s^23p^63d^{10}4s^24p^5

Br^-= 1s^22s^22p^63s^23p^63d^{10}4s^24p^6

(g) Sr

Strontium's atomic number is 38 in which only 2 electrons are present in its valence shell .So, in order to gain noble gas stability it will loose 2 electron to completes its octet.

In the Lewis symbol no dot shown as calcium has lost its 2 electron.

Sr=1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^2

Sr^{2+}=1s^22s^22p^63s^23p^63d^{10}4s^24p^65s^0

(h) F

Florine's atomic number is 7 in which only 7 electrons are present in its valence shell .So in order to gain noble gas stability it will gain 1 electron to completes its octet.

F=1s^22s^22p^5

F^-=1s^22s^22p^6

5 0
2 years ago
What is the frequency of a radio wave with a a wavelength of 3 m? (Hint: MHz
Ostrovityanka [42]

Answer:
a. 1 x 10^8

Explanation:

100 MHz = 100,000,000 Hz = 10^8 Hz

4 0
2 years ago
The bonding electrons in a non-polar compound are:
lara31 [8.8K]
Its A) Shared equally
Non-polar bonds are a type of chemical bond where two atoms share a pair of electrons with each other.
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what is the realtionship between the kentic energy of molecules in an object and the objects tempeture
MrMuchimi
Temperature is a measure of the average kinetic energy of the particles in an object .Temperatures also measure how kinetic energy is not how hot or cold it is. It’s measuring what the amount of Kinetic Energy there when you throw something in the air and it comes back down
6 0
3 years ago
Find the density of a substance whose volume is 5 cm^3 and whose mass is 25 g.
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Cm3 is Centimeter to the 3 power or Cubic Centimeter, just like for figuring concrete you need to know the volume of the pour expressed in cubic yards, length x width x height.

cm3 is centimeters instead of yards.

<span>So 25 grams/5 cubic centimeters (CM3) = 5
HOPE THIS HELPED</span>
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