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KIM [24]
3 years ago
7

Carbon-14 and carbon-12 have the same number of protons but a different number of neutrons. These different forms of the same el

ement are called___
Question 5 options:

A. radioactive


B. isotopes


C. nuclei


D. tracers
Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
7 0
The answer is B. isotopes
I hope i helped!
yawa3891 [41]3 years ago
3 0
B. Isotopes have different numbers of neutrons but the same number of protons.
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Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.
N76 [4]

Answer:

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

​

=22.4dm

3

V

f

​

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

​

V

f

​

​

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

​

V

f

​

​

)

⇒1000=−1×2.303×2×273×log(

22.4

V

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​

​

)

Explanation:

6 0
3 years ago
How many moles of carbon are in 3.5 L?
SashulF [63]

Answer:

0.16mole

Explanation:

To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.

The number of moles of a substance at STP is given as;

 Number of moles  = \frac{volume}{22.4}  

Given volume  = 3.5L

Now, insert the parameters;

     Number of moles  = \frac{3.5}{22.4}   = 0.16mole

8 0
3 years ago
How many moles of kf are contained in 244 ml of 0.135 m kf solution? the density of the solution is 1.22 g/ml?
galben [10]
The Molarity of a solution = number of moles / volume.  
Volume = 244ml = 0.244L
 So it follows that number of moles = Molarity * volume 
 Number of moles = 0.135 * 0.244 = 0.03945.
 Hence the number of moles = 0.03945
6 0
3 years ago
Read 2 more answers
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VLD [36.1K]

Answer:

arthropod

Explanation:

hope this helps

pls mark as brainliest

8 0
3 years ago
Which products are formed when aluminum is added to a silver chloride solution? none only AlCl3 AlCl3 and Ag AlAg3 and Cl2
anyanavicka [17]
The answer is "<span>AlCl3 and Ag".
 </span>
The reaction of aluminum and silver chloride is a single substitution type of reaction that is expressed as follows: Al (s) + 3AgCl (aq) = AlCl3 (aq) + 3Ag (s)When aluminium is added to silver chloride solution, the cations are exchanged in the process forming AlCl3 and Ag. 
4 0
3 years ago
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