Answer:
CH3O formula, C2H6O2 ACTUAL FORMULA
Explanation:
A sample of a compound has been analyzed and found to contain the following:
38.71% carbon, 9.75% hydrogen, and 51.54% g oxygen. If the molar mass of
the compound is determined by experiment to be between 62 and 63 g, what are the empirical and molecular formulas of the COMPOUND
empitical
take 100 gm of the compound
f O Divide by atomi wt of O to get moles
51.54/ 16.0 = 3.22
now if there is 1 atom of C and one of O, there will be 3 of H, so
CH3O is the empirical formula
the molar mass of the compound is 62-63. the mass of CH3O is
12 + 16 +3 = 31
2 X31 =62
so the compound is 2 times CH3O or C2H6O2
it most likely is
Ethylene glycol (name IUPAC: ethane-1,2-diol) is an organic formulated compound (CH2OH)2.
