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ELEN [110]
3 years ago
6

The FIRST space station placed into orbit around the earth followed by a team sent from earth to link up with the station was de

veloped by __________. A. Japan B. The Soviet Union C. The United States D. The European Space Agency
Physics
2 answers:
Radda [10]3 years ago
8 0
B. the soviet union .........
Marianna [84]3 years ago
4 0
The FIRST space station placed into orbit around the earth followed by a team sent from earth to link up with the station was developed by <span>The Soviet Union. The correct option among all the options that are given in the question is the second option or option "B". I hope the answer has come to your help.</span>
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One half of a balanced chemical equation is shown.
Zarrin [17]

Answer:

A: 3 Mg, 2 P, 14 O, 12 H

Explanation:

I took the test on Edgenuity

6 0
2 years ago
Read 2 more answers
An 8.75 kg point mass and a 14.0 kg point mass are held in place 50.0 cm apart. A particle of mass m is released from a point be
marysya [2.9K]

Answer

given,

mass of the = m₁ = 8.75 Kg

another mass of the object = m₂ = 14 Kg

distance between them = 50 cm

R₁ = 17 cm

R₂ = 50 -17 = 33 cm

a) Force applied due to the Mass 8.75  in +ve x- direction

F_1 = \dfrac{GM_1 m}{R_1^2}

F_1 = \dfrac{6.67\times 10^{-11} \times 8.75\ m}{0.17^2}

F_1 = 2.019\times 10^{8}\ m

Force applied due to mass 14 Kg in -ve x-direction

F_2 = \dfrac{GM_2 m}{R_2^2}

F_2 = \dfrac{6.67\times 10^{-11} \times 14\ m}{0.33^2}

F_2 = 0.857\times 10^{8}\ m

net force

F = F₁ + F₂

F = 2.019\times 10^{8}\ m - 0.857\times 10^{8}\ m

F = 1.162\times 10^{8}\ m

Using newton second law

a = \dfrac{F}{m}

a = \dfrac{ 1.162\times 10^{8}\ m}{m}

a =1.162\times 10^{8} \ m/s^2

b) As the acceleration of mass comes out to be  +ve hence, the direction will be toward the mass of 8.75 Kg

6 0
3 years ago
How to the magnitude of the applied force of a suspended string which applies a horizontal force to make an angle to the vertica
nataly862011 [7]

Answer:

Vector have magnitude and direction

Explanation:

Use the component X and component y to find the magnitude and direction

8 0
2 years ago
Drop a rock from a 5-m height and it accelerates at 9.81 m/s^2 and strikes the ground 1s later. Drop the sane rock from a height
KiRa [710]

Answer:

A. The same amount

Explanation:

The acceleration at which objects free falls to the ground on Earth is constant and its value is always 9.81 m/s^2, regardless of their mass (in this problem we neglect air resistance).

So, it doesn't matter if the two rocks are different or they are launched from different heights: their acceleration will be exactly the same.

This can be proved this way: first of all, the force of gravity exerted on every object is equal to the weight of the object,

F=mg

where m is the mass of the object and g the acceleration of gravity.

However, we also know for Newton's second law that

F=ma

where a is the acceleration of the object.

Combining the two equations,

ma=mg\\a=g

So, the acceleration of an object in free fall is exactly the acceleration of gravity.

8 0
2 years ago
What does a genus have
stiks02 [169]

1. Monophly - all descendants of an ancestral talon are grouped together (i.e. phylogenetic analysis should clearly demonstrate both monophyly and validity as a separate lineage).

2. Reasonable - with respect to evolutionary relevant criteria, i.e ecology morphology, or biogeography; DNA sequences are a consequence rather than a condition of divering evolutionary lineages

7 0
2 years ago
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