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3 years ago

a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?

1 answer:

5 0

We know that velocity is equal to the total displacement of an object over time.
$velocity = \frac{displacement}{time}$
Deriving from that equation, we can say that:
$t = \frac{d}{v}$
Okay, so here it goes:
$t = \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s$
The bicycle took 25.02 seconds to displace at 58.3 meters.

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Two of the three tuning forks have known frequencies. When a 610 Hz fork and the unknown fork are struck together, four beats pe

RUDIKE [14]

-- In combination with 610 Hz, the beat frequency is 4 Hz.

So the unknown frequency is either (610+4) = 614 Hz
or else (610-4) = 606 Hz.

In combination with 605 Hz, the beat frequency will be
either (614-605) = 9 Hz or else (606-605) = 1 Hz.

-- In actuality, when combined with the 605 Hz, the beat
frequency is too high to count accurately. That must be
the 9 Hz rather than the 1 Hz.

So the unknown is (605+9) = 614 Hz.

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4 years ago

A lone neutron spontaneously decays into a proton plus an _______

frosja888 [35]

Answer:

A lone neutron spontaneously decays into a proton plus an electron.

Explanation:

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A neutron undergoes the decaying process to produce an electron, a proton, and energy.

The reaction of neutron decay:

n0 → p+ + e− + νe

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3 years ago

A 500 kg car traveling at 20 m/s rear ends another car of 600 kg at rest. The collision is great enough that the two cars stick

aksik [14]

Answer: its 50

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3 years ago

The part of the earth system that includes earths solid, rocky, outer layer is the

Liono4ka [1.6K]

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3 years ago

A race car starts from rest on a circular track. The car increases its speed at a constant rate at as it goes 4.25 times around

miskamm [114]

Answer:

Angle = 1.07°

Explanation:

Total acceleration consists of translational acceleration (a) which is tangential and centripetal acceleration which is (radial).

Now, Tangential and radial acceleration are always perpendicular to each other. Thus, in a triangle system they are opposite and adjacent sides. From trigonometric ratios,

Opposite/Adjacent = tanθ

Now centripetal acceleration is given as v²/r

Thus, the angle to the radial is given as;

tanθ = translational acceleration/centripetal acceleration

So, tanθ = a/(v²/r) = ar/v²

Thus, θ = tan^(-1)(ar/v²)

Now, Distance of one round of circular motion of 'r' radius

= circumference of circle = 2πr

N = number of trips car makes around the circle

Thus,

total distance = 2πrN

Now, from equation of motion, we know that v² = u² + 2as

Where s is total distance and u is initial velocity which is zero in this case.

Thus, v² = 0² + 2as

Making s the subject;

s = v²/2a

Thus,

2πrN = v²/2a

So let's simplify to bring out ar/v² which is what we will use to calculate the angle. So,

2πrN x 2a = v²

4πN(ar) = v²

Thus, ar/v² = 1/(4πN)

From the question, N = 4.25

Thus,

ar/v² = 1/(4π x 4.25) = 0.0187

From earlier, we saw that the angle is given by;

θ = tan^(-1)(ar/v²)

Thus, θ = tan^(-1)(0.0187)

θ = 1.07°

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3 years ago