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Anna35 [415]
3 years ago
9

a bicycle travels at a velocity of -2.33 m/s and has a displacement of -58.3 m. how much time did it take?

Physics
1 answer:
Alexandra [31]3 years ago
5 0
We know that velocity is equal to the total displacement of an object over time.
velocity =  \frac{displacement}{time}
Deriving from that equation, we can say that:
t =  \frac{d}{v}
Okay, so here it goes:
t =  \frac{58.3m}{2.33 \frac{m}{s} } \\ t = 25.02s
The bicycle took 25.02 seconds to displace at 58.3 meters.
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The problem referred to in this question is missing and it is;

Two hockey pucks of identical mass are on a flat, horizontal ice hockey rink. The red puck is motionless; the blue puck is moving at 2.5 m/s to the left. It collides with the motionless red puck. The pucks have a mass of 15 g. After the collision, the red puck is moving at 2.5 m/s, to the left. What is the final velocity of the blue puck?

Answer:

The condition is that p_f - p_i which is the change in momentum will not be equal to zero but equal to the impulse (Ft).

Explanation:

In the problem described, by inspection, we can say that since there is no friction, we have a closed system and thus momentum is conserved.

Since momentum is conserved, we can say that;

Initial momentum(p_i) = final momentum(p_f)

Now, in this question we are told that some friction wants to be introduced on the ice and it's possible to still use conservation of momentum.

From impulse - momentum theory, we know that;

Impulse = change in momentum

Impulse is zero when no force is acting on the ice and we have; 0 = p_f - p_i

This will yield initial momentum = final momentum.

Now, since a force is applied, we know that impulse is; J = F × t

Thus;

Ft = p_f - p_i

Where F is the force due to friction.

Thus, the condition is that p_f - p_i will not be equal to zero

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