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sleet_krkn [62]
3 years ago
10

We are on an asteroid with thrusters pointed in 4 directions; Go Left, GO Right, Go Up, and Go Down. We start at coordinate (3,3

). We simultaneously fire all 4 thrusters. Go Left 3N, Go Right 4N, Go Up 2N, and Go Down 5N. Which 2 thrusters at what force could we have fired and achieved the same result?
Physics
1 answer:
Gala2k [10]3 years ago
6 0

K we start at (3,3) and then after all 4 thrusters are fired, we end up at (4,0)

If we fire the Right thruster 1N and the Down thruster 3N, we will achieve the same result.  

Hope that helps ya!!!

:)

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How could you test the hypothesis that elephants interpreted the ground signal as being farther away than the air signal?
bekas [8.4K]

Answer:

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

Explanation:

This hypothesis is based on the fact that the speed of sound in air is v = 343 m / s with a small variation with temperature.

The speed of sound in solid soil is an average of the speed of its constituent media, giving values ​​between

 wood      3900 m / s

 concrete 4000 m / s

 fabrics     1540 m / s

 earth       5000 m / s wave S

 ground    7000 m / s P wave

 

we can see that the speed on solid earth is an order of magnitude greater than in air.

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

From the initial information, the wave going through the ground should arrive first.

3 0
3 years ago
Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut
Harman [31]

Answer: a) 11.76 m/s  b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

V_{f}=V_{o}+at (1)  

{V_{f}}^{2}={V_{o}}^{2}+2ad (2)  

Where:  

V_{f} Is the final velocity of the object

V_{o}=0 Is the initial velocity of the object (it was dropped)

a=9.8 m/s^{2} is the acceleration due gravity

d is the height of the tower

t=0.02min=1.2 s is the time it takes to the object to reach the ground

b) Begining with (1):

V_{f}=0+at (3)  

V_{f}=at=(9.8 m/s^{2})(1.2 s) (4)  

V_{f}=11.76 m/s (5)  This is the final velocity of the object

a) Substituting (5) in (2):

(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d (6)  

Clearing d:

d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})} (7)  

d=7.056 m (8)  This is the height of the tower

4 0
3 years ago
Which of the following quantities are unknown?
Sauron [17]

Answer:

Charge of the alpha particle

Explanation:

6 0
3 years ago
Monochromatic light of a given wavelength is incident on a metal surface. however, no photoelectrons are emitted. if electrons a
kifflom [539]
If the object, ends up with a positive charge, then it is missing electrons. if it is missing electrons, then it must have been removed form the object during the rubbing process.
5 0
3 years ago
Light of wavelength 436.1 nm falls on two slits spaced 0.31 mm apart. What is the required distance from the slits to the screen
kakasveta [241]

Answer:

The correct answer is "4.26 m".

Explanation:

Given:

Wavelength,

\lambda = 436.1 \ nm

or,

  =436.1\times 10^{-9} \ m

Distance,

d = 0.31 \ mm

or,

  =0.31\times 10^{-3} \ m

Distance between the 1st and 2nd dark fringes,

(y_2-y_1) = 6\times 10^{-3} \ m

As we know,

⇒ \frac{d}{L} (y_2-y_1) = \lambda

or,

⇒ L=\frac{d(y_2-y_1)}{\lambda}

By substituting the values, we get

       =\frac{0.31\times 6\times 10^{-6}}{436.1\times 10^{-9}}

       =\frac{0.31\times 6\times 10^3}{436.1}

       =\frac{1860}{436.1}

       =4.26 \ m

3 0
3 years ago
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