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3 years ago

Which trends appear as the elements in Period 3 are considered from left to right?

Chemistry

1 answer:

andreev551 [17]3 years ago

8 0

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

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Solutions of sodium sulfate and silver nitrate are mixed together.

Vera_Pavlovna [14]

Answer:

The correct option is a) Precipitate: silver sulfate

Net Ionic: 2Ag+ + SO42 →Ag2SO4

Explanation:

When sodium sulfate reacts with silver nitrate, the following reaction occurs:

2AgNO3 + Na2SO4 → Ag2SO4 + 2NaNO3

The NaNO3 is easily soluble in water. However, silver ions form an insoluble solid with SO4. The Ag+ in this compound will be a cation having a positive charge. The SO4- will be an anion having an negative charge.

The table with solubility rules show that the sulfates of Ag+, Ca+, Sr2+, Ba2+, Hg22+ and Pb2+ are insoluble.

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3 years ago

the bond formed between the carboxylic acid group of one amino acid and the amino group of the next amino acid is a(n) bond.

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Peptide bonds are amide connections between two amino acids' -carboxyl and -amino groups.

The covalent link created by the dehydration reaction (loss of a water molecule) between the carboxyl group of one amino acid and the amino group on the next is known as a peptide bond. Peptide bonds are created in polypeptides through a condensation reaction between the carboxyl groups of one amino acid and the amino groups of the following amino acid, all while removing water. When the carboxyl group of one molecule combines with the amino group of the other molecule, releasing a molecule of H2O as a result, a peptide bond is created between the two molecules.

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1 year ago

What is the force that accelerates objects towards Earth?

geniusboy [140]

The force that accelerates objects towards Earth is gravity.

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3 years ago

Chromium is dissolved in sulfuric acid according to the following equation: Cr + H2SO4 ⇒ Cr2 (SO4) 3 + H2

Usimov [2.4K]

Answer:

$\large \boxed{\text{a)188.4 g; b) 98.67 $\, \%$}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 98.08 392.18

2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂

To solve the stoichiometry problem, you must

Use the molar mass of H₂SO₄ to convert the mass of H₂SO₄ to moles of H₂SO₄
Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃

a) Mass of Cr₂(SO₄)₃

(i) Mass of pure H₂SO₄

$\text{Mass of pure} = \text{165 g impure} \times \dfrac{\text{85.67 g pure} }{\text{100 g impure}} = \text{141.36 g pure}$

(ii) Moles of H₂SO₄

$\text{Moles of H$_{2}$SO}_{4} = \text{141.36 g H$_{2}$SO}_{4} \times \dfrac{\text{1 mol H$_{2}$SO}_{4}}{\text{98.08 g H$_{2}$SO}_{4}} = \text{1.441 mol H$_{2}$SO}_{4}$

(iii) Moles of Cr₂(SO₄)₃

The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄ $\text{Moles of Cr$_{2}$(SO$_{4}$)}_{3} = \text{1.441 mol H$_{2}$SO}_{4} \times \dfrac{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}}{\text{3 mol H$_{2}$SO}_{4}} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3}$

(iv) Mass of Cr₂(SO₄)₃ $\text{Mass of Cr$_{2}$(SO$_{4}$)}_{3} = \text{0.4804 mol Cr$_{2}$(SO$_{4}$)}_{3} \times \dfrac{\text{392.18 g Cr$_{2}$(SO$_{4}$)}_{3}}{\text{1 mol Cr$_{2}$(SO$_{4}$)}_{3}} = \textbf{188.4 g Cr$_{2}$(SO$_{4}$)}_{3}\\\text{The mass of Cr$_{2}$(SO$_{4}$)$_{3}$ formed is $\large \boxed{\textbf{188.4 g}}$}$

b) Percentage yield

It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

$\text{Percentage yield} = \dfrac{\text{Actual yield}}{\text{Theoretical yield}} \times 100 \, \% = \dfrac{\text{185.9 g}}{\text{188.4 g}} \times 100 \, \% = \mathbf{98.67 \, \%}\\\\\text{The percentage yield is $\large \boxed{\mathbf{98.67 \, \%}}$}$

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4 years ago

What is an example of a Low Energy-created depositional environment?

sweet-ann [11.9K]

Answer:

River flood plains, swamps, lakes, lagoons, marshes, and offshore.

Explanation:

Slow-moving currents prevent coarse-grained sediment from migrating into low-energy depositional environments. Fine materials can be carried long distances before they can settle out in the absence of waves and currents.

4 0

3 years ago