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Lady bird [3.3K]
3 years ago
14

Which trends appear as the elements in Period 3 are considered from left to right?

Chemistry
1 answer:
andreev551 [17]3 years ago
8 0

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

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3 years ago
How could you ensure that all the spectroscopes used the same calibration line and equation? What would you need to be sure was
NISA [10]
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8 0
2 years ago
Which trends appear as the elements in Period 3 are considered from left to right?
andreev551 [17]

Answer:

Metallic character decreases, and electronegativity increases.

Explanation:

Hello!

In this case, according to the organization of the periodic table, we can see that from left to right, the electronegativity increases as nonmetals are able to attract electrons more easily than metals.

Moreover, in contrast to the previous periodic trend, the metallic character decreases from left to right because the elements tend to decrease the capacity to lose electrons and consequently start attracting them.

Thus, the answer would be: "Metallic character decreases, and electronegativity increases".

Best regards!

8 0
3 years ago
A helium balloon is filled on the ground where the atmospheric pressure is 768 torr. The volume of the balloon is 8.00 m3. When
Anvisha [2.4K]

Answer:

The correct option is: <u>B. 366 torr</u>

Explanation:

Given: <u>On the ground</u>- Initial Volume: V₁ = 8.00 m³, Initial Atmospheric Pressure: P₁= 768 torr;

<u>At 4200 m height</u>- Final Volume: V₂ = 16.80 m³, Final Atmospheric Pressure: P₂ = ?

Amount of gas: n, and Temperature: T = constant

<u>According to the Boyle's Law</u>, for a given amount of gas at constant temperature:         P₁ V₁ = P₂ V₂

⇒  P₂ = P₁ V₁ ÷ V₂

⇒  P₂ = [(768 torr) × (8.00 m³)] ÷ (16.80 m³)

⇒  P₂ = 365.71 torr ≈ 366 torr

<u>Therefore, the final air pressure at 4200 m height: P₂ = 366 torr.</u>

6 0
3 years ago
What is the correct answer ??
Ber [7]

Answer:

[H_3 O^+] = 1.0 ×10^-13

Explanation:

If we multiply the left side we get, 1e - 13. We add 13 to the right side while subtracting the remaining value from the left side (H3O+) than combine like terms. As you will get pH = 13.00

7 0
3 years ago
Read 2 more answers
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