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Aloiza [94]
3 years ago
9

How much heat was transferred from 50.0 g of water if the temperature of the water went from 30.0 ° C to 55.0 °? The specific he

at capacity of the water is 4.18 J/(g•K)
Chemistry
1 answer:
Lena [83]3 years ago
4 0

Answer:

Heat transfer = Q = 62341.6 J

Explanation:

Given data:

Heat transfer = ?

Mass of water = 50.0 g

Initial temperature = 30.0°C

Final temperature = 55.0°C

Specific heat capacity of water = 4.184 J/g.K

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 55.0°C -  30.0°C

ΔT = 25°C (25+273= 298 K)

Q = 50.0 g × 4.184 J/g.K ×298 K

Q = 62341.6 J

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Answer: a) Frequency=666\times10^{12}Hz-789\times10^{12}Hz

b) Wavelength=380nm-450nm

Explanation: Visible light is a form of electromagnetic wave.

Wavelength is defined as the distance between two successive crests of a wave. It is represented as symbol \lambda.

Frequency is defined as the number of complete cycles happening per second. It is represented by the symbol \nu.

Wavelength and Frequency follow inverse relation,

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3 years ago
Help please
Mekhanik [1.2K]

Answer:

it's the regolith

hope this helps you

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3 years ago
A 2.75 M solution is diluted to 0.706 M, if the starting volume was 0.833L, what is the new volume?
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8 0
2 years ago
Determine the percent water in MgSO4*7H20?
Semmy [17]

Answer:

\% H_2O=51.2\%

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol

Thus, the percent water is:

\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\

So we plug in to obtain:

\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%

Best regards!

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Answer:. In the case of neon, it is electrical energy that pulls the electrons off.

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8 0
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