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3 years ago

Can someone answer these two separate questions pls ill give brainliest

Chemistry

1 answer:

Tems11 [23]3 years ago

8 0

The average speed

3. 89.7 m/min

4. 6.13 ft/min

<h3>Further explanation</h3>

Given

3. 1076 m in 12 min

4. 92 ft in 15 min

Required

average speed

Solution

I am solving for : the average speed

The equation I need is :

$\tt avg~speed=\dfrac{total~distance}{total~time}$

This is how I set the equation

$\tt avg~speed=\dfrac{1076~m}{12~min}$

This is my answer = 89.7 m/min

I am solving for : the average speed

The equation I need is :

$\tt avg~speed=\dfrac{total~distance}{total~time}$

This is how I set the equation

$\tt avg~speed=\dfrac{92~ft}{15~min}$

This is my answer = 6.13 ft/min

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A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el

icang [17]

Answer:

The temperature of the air at this given elevation will be 53.32425°C

Explanation:

We can calculate the final temperature through the combined gas law. Therefore we will need to know 1 ) The initial volume, 2 ) The initial temperature, 3 ) Initial Pressure, 4 ) Final Volume, 5 ) Final Pressure.

Initial Volume = 1.2 L ; Initial Temperature = 25°C = 298.15 K ; Initial pressure = 1.0 atm ; Final Volume = 1.8 L ; Final pressure = 0.73 atm

We have all the information we need. Now let us substitute into the following formula, and solve for the final temperature ( T $_2$ ),

P $_1$ V $_1$ / T $_1$ = P $_2$ V $_2$ / T $_2$ ,

T $_2$ = P $_2$ V $_2$ T $_1$ / P $_1$ V $_1$ ,

T $_2$ = 0.73 atm $*$ 1.8 L $*$ 298.15 K / 1 atm $*$ 1.2 L = ( 0.73 $*$ 1.8 $*$ 298.15 / 1 $*$ 1.2 ) K = 326.47425 K,

T $_2$ = 326.47425 K = 53.32425 C

7 0

3 years ago

Which plant has a longer orbit. Jupiter or Saturn

romanna [79]

Answer:

Saturn

Explanation:

One whole orbit is a year on earth. Well it takes Saturn 10,759 days to make one whole orbit. It takes Jupiter 4,333 days to make a whole orbit.

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3 years ago

2. A solution is 0.01 M in Ba2+ and 0.01 M in Ca2+. Sodium sulfate is added to selectively precipitate one of the cations, while

lozanna [386]

Answer:

Explanation:

The solution contain 0.01 M concentration of Ba²⁺

0.01M concentration of Ca²⁺

Ksp ( solubility constant) for BaSO₄ = 1.07 × 10⁻¹⁰

Ksp for CaSO₄ = 7.10 × 10⁻⁵

(BaSO₄) = (Ba²⁺) (SO₄²⁻)

1.07 × 10⁻¹⁰ = 0.01 M (SO₄²⁻)

1.07 × 10⁻¹⁰ / 0.01 = ( SO₄²⁻)

1.07 × 10⁻⁸ M = ( SO₄²⁻)

so the minimum of concentration of concentration sulfate needed is 1.07 × 10⁻⁸ M

For CaSO₄

CaSO₄ = ( Ca²⁺) ( SO₄²⁻)

7.10 × 10⁻⁵ = 0.01 (SO₄²⁻)

(SO₄²⁻) = 7.10 × 10⁻⁵ / 0.01 = 7.10 × 10⁻³ M

so BaSO₄ will precipitate first since its cation (0.01 M Ba²⁺) required a less concentration of SO₄²⁻ (1.07 × 10⁻⁸ M ) compared to CaSO₄

b) The minimum concentration of SO₄²⁻ that will trigger the precipitation of the cation ( 0.01 M Ba²⁺) that precipitates first is 1.07 × 10⁻⁸ M

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4 years ago

A room is a cube that measures 4 meters in each dimension. If the temperature changes from 10 C to 30 C, and the pressure decrea

Katen [24]

Answer:

More air will enter the room since the volume of the room increases.

Explanation:

We'll begin by calculating the initial volume (V₁) of the room. This can be obtained as follow

Length (L) of room = 4 m

Initial volume (V₁) =..?

V₁ = L³

V₁ = 4³

V₁ = 64 m³

Next, we shall determine if there is an increase in the volume of the room or not. This can be obtained as follow:

Data obtained from the question include:

Initial volume (V₁) = 64 m³

Initial temperature (T₁) = 10 °C + 273 = 283 K

Final temperature (T₂) = 30 °C + 373 = 303 K

Initial pressure (P₁) = 760 mmHg

Final pressure (P₂) = 718 mmHg

Final volume (V₂) =?

P₁V₁/T₁ = P₂V₂/T₂

760 × 64 / 283 = 718 × V₂ / 303

48640 / 283 = 718 × V₂ / 303

Cross multiply

283 × 718 × V₂ = 48640 × 303

203194 × V₂ = 14737920

Divide both side by 203194

V₂ = 14737920 / 203194

V₂ = 72.53 m³

SUMMARY

Initial volume (V₁) of room = 64 m³

Final volume (V₂) of room = 72.53 m³

From the calculations made above, we can see that the volume of the room increases from 64 m³ to 72.53 m³. Thus more air will enter the room since the volume of the room increases.

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3 years ago