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Evgesh-ka [11]
3 years ago
6

Can someone answer these two separate questions pls ill give brainliest

Chemistry
1 answer:
Tems11 [23]3 years ago
8 0

The average speed

3. 89.7 m/min

4. 6.13 ft/min

<h3>Further explanation</h3>

Given

3. 1076 m in 12 min

4. 92 ft in 15 min

Required

average speed

Solution

3.

<em>I am solving for</em> : the average speed

<em>The equation I need is :</em>

\tt avg~speed=\dfrac{total~distance}{total~time}

<em>This is how I set the equation</em>

<em />\tt avg~speed=\dfrac{1076~m}{12~min}<em />

<em>This is my answer</em> = 89.7 m/min

4.

<em>I am solving for</em> : the average speed

<em>The equation I need is :</em>

\tt avg~speed=\dfrac{total~distance}{total~time}

<em>This is how I set the equation</em>

<em />\tt avg~speed=\dfrac{92~ft}{15~min}<em />

<em>This is my answer</em> = 6.13 ft/min

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Answer:

4Zn_(_s_)~+~7OH^-~_(_a_q_)~+~NO_3^-_(_a_q_)~+~6H_2O_(_l_)~-->4Zn(OH)_4^-^2_(_a_q_)~+~NH_3_(_g_)

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If we want to balance in <u>basic medium </u>we have to follow the rules:

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Lets balance the first semireaction A. :

Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-

Now, lets balance semireaction B:

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Finally, we have to add the two semireactions:

_________________________________________

8~(Zn~+~4OH^-~->Zn(OH)_4^-^2~+~2e^-)

2~(NO_3^-~+~8e^-~+~6H_2O~->~NH_3~+~9OH^-)

_________________________________________

(8Zn~+~32OH^-~->8Zn(OH)_4^-^2~+~16e^-)

(2NO_3^-~+~16e^-~+~12H_2O~->~2NH_3~+~18OH^-)

Cancel out the species on both sides:

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Simplifying the equation :

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