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Evgesh-ka [11]
2 years ago
6

Can someone answer these two separate questions pls ill give brainliest

Chemistry
1 answer:
Tems11 [23]2 years ago
8 0

The average speed

3. 89.7 m/min

4. 6.13 ft/min

<h3>Further explanation</h3>

Given

3. 1076 m in 12 min

4. 92 ft in 15 min

Required

average speed

Solution

3.

<em>I am solving for</em> : the average speed

<em>The equation I need is :</em>

\tt avg~speed=\dfrac{total~distance}{total~time}

<em>This is how I set the equation</em>

<em />\tt avg~speed=\dfrac{1076~m}{12~min}<em />

<em>This is my answer</em> = 89.7 m/min

4.

<em>I am solving for</em> : the average speed

<em>The equation I need is :</em>

\tt avg~speed=\dfrac{total~distance}{total~time}

<em>This is how I set the equation</em>

<em />\tt avg~speed=\dfrac{92~ft}{15~min}<em />

<em>This is my answer</em> = 6.13 ft/min

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What will happen to Uk if you double the mass?

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You see that both m and v are variable, which means that both m and v can be any number. Regardless of the numbers you put in for m or v, the formula to calculate the kinetic energy (Uk) remains valid.

You could ask

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2. What will happen to Uk if you double the velocity?

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EXTRA

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What is the Uk?

Well if you know the formula you can use your calculator to find out:

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At first it was 5 m/s and now it doubles, which means it now has that value *2

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