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julsineya [31]
3 years ago
14

A gas occupies 4.0 L of air at 1.0 atm pressure and 30.0°C. If the gas occupies 6.0 L of air at 37.0°C, what is the pressure of

the gas?
Chemistry
1 answer:
V125BC [204]3 years ago
3 0

Answer:

Gas pressure is measured in units such as torr, mmHg, atm, and Pa. ... You can see mass is small, Volume is large. - hense a small ... The pressure increases if volume decreases. ... For each of the following changes of the initial balloon, select ... A sample of nitrogen (N2) has a volume of 60.0 L at a pressure of 725 mmHg.

Explanation:

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The normal boiling point of ethanol (C2H5OH) is 78.3 oC and its molar enthalpy of vaporization is 38.56 kJ/mol. What is the chan
Sloan [31]

Answer:

The  change in entropy in the system is -231.5 J/K

Explanation:

Step 1: Data given

The normal boiling point of ethanol (C2H5OH) is 78.3 °C = 351.45 K

The molar enthalpy of vaporization of ethanol is 38.56 kJ/mol = 38560 J/mol

Mass of ethanol = 97.2 grams

Pressure = 1 atm

Step 2: Calculate the entropy change of vaporization

The entropy change of vaporization = molar enthalpy of vaporization of ethanol / temperature

The entropy change of vaporization = 38560 J/mol / 351.45 K

The entropy change of vaporization = -109.72 J/k*mol

Step 3: Calculate moles of ethanol

Moles ethanol = mass / molar mass ethanol

Moles ethanol = 97.2 grams / 46.07 g/mol

Moles ethanol = 2.11 moles

Step 4: Calculate  change in entropy

For 1 mol = -109.72 J/K*mol

For 2.11 moles = -231.5 J/K

The  change in entropy in the system is -231.5 J/K

7 0
3 years ago
How many minutes will it take for the quantity of n2o5 to drop to 1.9×10−2 mol ?
Novay_Z [31]

<span>Missing question: The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g) + O2(g) at 70°</span><span>C is 6.82×10−3 s−1. Suppose we start with 2.70×10−2 mol of N2O5(g) in a volume of 1.8 L .
</span>c₀(N₂O₅) = 0,027 mol ÷ 1,8 L.<span>
c</span>₀(N₂O₅) = 0,015 mol/L.<span>
c(N</span>₂O₅) = 0,019 mol/ 1,8 L = 0,01055 mol/L.<span>
k = 6,82·10</span>⁻³ s⁻¹.<span>
ln c(N</span>₂O₅) = ln c₀(N₂O₅) - k·t.<span>
t = (ln c</span>₀(N₂O₅) - ln c(N₂O₅)) ÷ k.<span>
t = 0,35 ÷ 0,00682 s</span>⁻¹.<span>
t = 51 s = 0,86 min.</span>

3 0
3 years ago
The next 3 questions will walk you through using the Henderson-Hasselbalch equation for the following question. For each step pr
kicyunya [14]

Answer:

<em>The pKa is 13.0.</em>

Explanation:

pKa + pKb = 14

Given, Kb of trimethylamine = 6.3 × 10^{-5}

pKb = - log (6.3 × 10^{-5})

= 1.0

⇒ pKa = 14 - pKb = 14 - 1.0

<u>pKa = 13.0</u>

<em><u></u></em>

<em>Check: For most weak acids,  pKa ranges from 2 to 13.</em>

8 0
3 years ago
If ya could change somethin bout ya previous science classes what would it be?
k0ka [10]

If I could change something in my previous science classes, it would have been the fact that I struggled in the question concerning exponents. It was simple one, but I don't know how I didn't understood that. For example, if there is a question with a calculation "xy²", then I would first multiply x and y, and then calculate the exponent. I did 3 of the questions wrong because of this, it was when I was in 7th grade. I wish I had not done this kind of silly mistake. I an in 10th grade and understand it well now, though.

8 0
3 years ago
When electricity passes through a gas it may become hot enough to give off light how could scientist determine the element from
galina1969 [7]
They can tell the element by how it reacts
4 0
4 years ago
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