This uses something called the combined gas law. The combined gas law is as follows: (P1*V1/T1) = (P2*V2/T2)
According to question 2, you are given the following values initially:
P1 = 680 mm Hg * (1 atm/760 mm Hg) = 0.895 atm
V1 = 20.0 L
T1 = 293 K
STP or standard temperature and pressure implies that the other values we know are:
P2 = 1 atm
T2 = 273 K
Our unknown is V2
If we plug in our known values into the combined gas law:
(P1*V1/T1) = (P2*V2/T2)
(0.895 atm * 20.0 L)/293K = (1 atm * X liters)/273 K
0.0611 L*atm/K = (1 atm * X liters)/273 K
16.7 L = X liters
Therefore, the volume occupied at STP is 16.7 liters
This makes sense because the gas would occupy a smaller volume at a lower temperature, since the gas would have a lower average kinetic energy.
Hm, this could be more than one option, but gaining electrons makes a negative charge, so
If atoms of a halogen nonmetal (Group 17) gains one electron, the atoms the have "a negative one charge".
Answer:
a welding torch requires 4122.8L of ethylene gas at 0.64 atm
Answer:
- the specific gravity of the block is 0.75
- the specific gravity of the solution is 1.5
Explanation:
Given the data in the question;
first we find the specific gravity of a block SGB
SGB = ( block vol below / total block vol ) × the specific gravity of water
we substitute
SG = ( 1.5 / (1.5 + 0.5 ) ) × 1
SG = ( 1.5 / (1.5 + 0.5 ) ) × 1
SG = (1.5 / 2) × 1
SG = 0.75
Therefore, the specific gravity of the block is 0.75
specific gravity of solution SG
SG = (total block vol / block below ) × SG
we substitute
SG = ( 2 / 1 ) × 0.75
SG = 2 × 0.75
SG = 1.5
Therefore, the specific gravity of the solution is 1.5