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zepelin [54]
3 years ago
11

Which of the following are good conductors

Chemistry
2 answers:
dimulka [17.4K]3 years ago
5 0

Answer:

iron, graphite,NaCl solution etc are some examples of good conductor of electricity

Zolol [24]3 years ago
4 0

Answer:

iron is because it is very important and powerful

..

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A solution containing a mixture of metal cations was treated with dilute HCl and no precipitate formed. Next, H2S was bubbled th
erica [24]

Answer:

Explanation:

  Ions which will  be definitely  absent -

Ag⁺ , Hg₂⁺ , Pb⁺², because their chlorides are insoluble in water.

Ba⁺² ,Ca⁺² because their carbonates are insoluble in water,

Ions which will be definitely present  

Cu⁺² , Pb⁺² . Hg⁺² , Sb⁺³ , Sn⁺² , because their sulphides are insoluble at pH = 8.

For the rest nothing can be said.

 

5 0
3 years ago
Activity 2 Directions: Select among the choices thbest type of material to be used in making the objects at the left and explain
joja [24]

Answer:

A Walk in the City

Make a list of the number of cars, jeeps, tricycle, and even trucks you've seen on your way to school. On a Decision Making Chart, answer the question, "Does the volume of traffic affect the air quality in my local community?" Write your reasons for saying YES on the Reasons for column, and the reasons for saying NO on the Reasons Against column. At the bottom of a chart, make a position by writing your decision on the same question.

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[reason for]

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3 0
2 years ago
Im sooooooooooooooooooooooooo cufused on science
Elena-2011 [213]

Answer:

What do you need please to understand?

6 0
3 years ago
The results of a classroom group activity performed to test the acidic or basic nature of two substances are shown in the table.
zvonat [6]
Substance a is a base, and substance b is an acid
4 0
3 years ago
2NO (g) + O2 (g) →2NO2 (g) At equilibrium [NO] = 2.4 × 10 -3 M, [O2] = 1.4 × 10 -4 M, and [NO2] = 0.95 M.
azamat

Answer:

K=1.12x10^9

Explanation:

Hello there!

Unfortunately, the question is not given in the question; however, it is possible for us to compute the equilibrium constant as the problem is providing the concentrations at equilibrium. Thus, we first set up the equilibrium expression as products/reactants:

K=\frac{[NO_2]^2}{[NO]^2[O_2]}

Then, we plug in the concentrations at equilibrium to obtain the equilibrium constant as follows:

K=\frac{(0.95)^2}{(0.0024)^2(0.00014)}\\\\K=1.12x10^9

In addition, we can infer this is a reaction that predominantly tends to the product (NO2) as K>>>>1.

Best regards!

4 0
3 years ago
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