1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zepelin [54]
2 years ago
11

Which of the following are good conductors

Chemistry
2 answers:
dimulka [17.4K]2 years ago
5 0

Answer:

iron, graphite,NaCl solution etc are some examples of good conductor of electricity

Zolol [24]2 years ago
4 0

Answer:

iron is because it is very important and powerful

..

You might be interested in
What mass of magnesium hydroxide is required to create a 441 mL solution with a pH of 12.52?
marshall27 [118]

Answer:

0.423g

Explanation:

akording to mass = concetration x volume

4 0
3 years ago
T he thermochemical equation for the reaction between hydrazine, N2H4, and dinitrogen tetroxide is given as: 2N2H4(2) N204 (1) 3
SpyIntel [72]

Answer:

4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ

Explanation:

2N2H4(2) + N204 (1) --> 3N2 (g) + 4H20 (g),AHO-1049 kJ

when 6 mol of nitrogen are formed?

The ratio of Nitrogen in the previous therrmochemical equation to when 6 mol f nitrogen are formed is 2; 6/3 = 2.

So to get the new thermoochemical equation, multiply all parameters in the given equation by 2.

We have;

4N2H4(2) + 2N204 (1) --> 6N2 (g) + 8H20 (g), AHO-2098 kJ

6 0
2 years ago
Describe how you would prepare 350 ml of 0.100 m c12h22o11 starting with 3.00l of 1.50 m c12h22o11
Leona [35]

To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

M1 V1 = M2 V2

So from the formula, we will know how much volume of the 1.50 M we actually need.

 

1.50 M * V1 = 0.100 M * 350 mL

V1 = 23.33 mL

 

So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

350 mL – 23.33 mL = 326.67 mL water

 

 

Steps:

1. Take 23.33 mL of 1.50 M solution

<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M solution</span>

7 0
3 years ago
Please help thank you (15 points)
sashaice [31]

Answer:

If the answer helps you PLEASE mark me as brainliest

Stay Safe, Stay Happy And stay healthy

6 0
2 years ago
Which best explains why water is able to “stick” to the side of glass?
AveGali [126]

Explanation:

Adhesion means the ability to stick on the surface of another substance.

Water exhibits adhesive forces due to which it is able to stick to the glass.  Due to adhesive forces water spreads over the surface of glass and sticks to it.

These adhesive forces between the glass and water enough that it deforms the spherical shape of water molecules and help them stick to the surface of glass. As a result, adhesive forces overcome the repulsion between like molecules.

Hence, water is able to “stick” to the side of glass due to strong adhesive forces.


4 0
3 years ago
Read 2 more answers
Other questions:
  • How much does a gold bar wiegh and how much is it wotrth
    11·1 answer
  • You play a chess game 20 games total, you win only 2 out of the total. what is your ratio of games lost to games won
    10·2 answers
  • What is the empirical formula for a compound that contains 0.0134 g of iron, 0.00769 g of
    13·1 answer
  • How many grams of Chloride are in 760 grams of Iron (III) Chloride
    11·1 answer
  • A solution of NaCl(aq) is added slowly to a solution of lead nitrate, Pb(NO3)2(aq) , until no further precipitation occurs. The
    8·1 answer
  • Which color has the longest wavelength?
    12·1 answer
  • In atoms, electrons surround the nucleus in
    13·1 answer
  • When lithium (Li) is mixed with magnesium oxide (MgO), a single replacement reaction occurs. What will be the product or product
    7·1 answer
  • How many moles of NaOH are in a 50.0 g sample of NaOH?
    7·2 answers
  • 6. The human arm, a bat's wing, a whale's flipper, and a horse's
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!