13 half-lives have passed
<h3>Further explanation
</h3>
General formulas used in decay:
T = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t1/2 = 4 days
Nt=18 mg (0.01% of the original isotope)
18 mg (Nt) = 0.01% No
No = the original isotope :
The duration of decay (T) :
Half-lives passed :
Answer:
Explanation:
Dinitrogen pentaoxide is a nitrogen oxide.
...
3.1Computed Properties.
Property Name Property Value Reference
Formal Charge 0 Computed by PubChem
Remember:
6.022×10²³ molecules = 1 mol (Avogadro's number)
NH₃ = ammonia
To get molar mass of NH₃, add the mass of nitrogen + 3 times the mass of hydrogen (because there are 3 hydrogens in NH₃).
14.01 + 3(1.01) = 17.04 grams NH₃ = molar mass
1) Set up your equation. You want to cancel out molecules, and get to grams through moles.
So multiply 3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia and divide it by 6.022×10²³ molecules of ammonia and 1 mol of ammonia.
3.4×10²⁴ molecules of ammonia × 1 mol of ammonia × 17.04 grams of ammonia
6.022×10²³ molecules of ammonia 1 mol of ammonia
Your answer should come out to be: 96.20724 grams of ammonia
Round to 2 sig figs: 96 grams of ammonia
Answer:
3.36 × 10^-19 J
Explanation:
From the formula;
E= hc/wavelength
h= 6.6 ×10^-34 Js
c= 3 × 10^8 ms-1
Wavelength= 589 ×10^-9 m
E= hc/ wavelength
E=6.6 ×10^-34 × 3 × 10^-8/ 589 ×10^-9
E= 3.36 × 10^-19 J