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Svetach [21]
2 years ago
6

If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(5a, 2a),

where a > 0, what is the value of a?
Mathematics
1 answer:
Aliun [14]2 years ago
5 0

Answer:

The value of a is 80

Step-by-step explanation:

The distance of a point (x_o,y_0) from the y-axis can be written as d_y=|x_o|  because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point  from the x-axis can be written as d_x=|y_0|

since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

d_A=|-30|=30

- The distance of point B (5a,2a) from the x-axis can be written as

d_B=|2a|=2a

Since a>0

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

\frac{2}{3}d_A=\frac{1}{4}d_B

Therefore,

\frac{2}{3}(30)=\frac{1}{4}(2a)

And solving for a,

20=\frac{1}{2}a\\a=40

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Red bricks : Grey bricks
        5        :            2

Total parts = 5 + 2 = 7

7 parts = 224
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Find 1 part:
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1 part = 234 ÷ 7
1 part = 32

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Find 5 parts:
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5 parts = 32 x 5 
5 parts = 160

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Answer: 160 Red bricks
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(7x - 1) + (-x - 2) in simplest terms
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Step-by-step explanation:

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A segment has endpoints (-9,-20) and (14,12). What is the midpoint of this segment
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2 years ago
The car dealership kept track of how many cars they sold each week for 6
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Answer:

75

Step-by-step explanation:

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2 years ago
A carpenter is putting a skylight in a roof. If the roof measures 10 + 8 by 8 + 6 and the skylight measures + 5 by 3 + 4, what i
Usimov [2.4K]

Answer:

The area is: 77x^2 + 105x + 28, option b.

Step-by-step explanation:

Rectangular area:

The area of a rectangular space is given bt the multiplication of its measures.

Area of the roof:

Dimensions of 10x + 8 and 8x + 6. So

A_{r} = (10x+8)(8x+6) = 80x^2 + 60x + 64x + 48 = 80x^2 + 124x + 48

Area of the skylight:

Dimensions of x + 5 and 3x + 4. So

A_{s} = (x+5)(3x+4) = 3x^2+4x+15x+20 = 3x^2 + 19x + 20

What is the area of the remaining roof after the skylight is built?

Total subtracted by the skylight, which is a subtraction of a polynomial, in which we subtract the like terms. So

A_{r} - A_{s} = 80x^2 + 124x + 48 - (3x^2 + 19x + 20) = 80x^2 - 3x^2 + 124x - 19x + 48 - 20 = 77x^2 + 105x + 28

The area is: 77x^2 + 105x + 28, option b.

3 0
2 years ago
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