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Svetach [21]
2 years ago
6

If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(5a, 2a),

where a > 0, what is the value of a?
Mathematics
1 answer:
Aliun [14]2 years ago
5 0

Answer:

The value of a is 80

Step-by-step explanation:

The distance of a point (x_o,y_0) from the y-axis can be written as d_y=|x_o|  because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point  from the x-axis can be written as d_x=|y_0|

since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

d_A=|-30|=30

- The distance of point B (5a,2a) from the x-axis can be written as

d_B=|2a|=2a

Since a>0

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

\frac{2}{3}d_A=\frac{1}{4}d_B

Therefore,

\frac{2}{3}(30)=\frac{1}{4}(2a)

And solving for a,

20=\frac{1}{2}a\\a=40

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