If we represent Tobin's speed as x, we can write her opponent's speed as
x-2 (since Tobin is 2 more than them). In addition, since it's in miles per hour, and 45 minutes is 3/4 of an hour, we can say that 3/4ths of her speed in miles per hour is how long the race is, so (3/4)(x-2)=distance of race. In addition, since it only took Tobin 30 minutes, and 30 minutes is half an hour, x/2 (half of her miles per hour) is the length of the race, so (3/4)(x-2)=(1/2)x. Expanding it, we get 3x/4-6/4=x/2. Subtracting x/2 (or 2x/4) from both sides, we get x/4-6/4=0 and by adding 6/4 to both sides we get x/4=6/4. Multiplying 4 to both sides, we get that x=6=Tobin's speed in miles per hour
Answer:
A
Step-by-step explanation:
(fg)(x) = f(x) × g(x)
= (x - 8)(x² + x - 1)
Each term in the second factor is multiplied by each term in the first factor, that is
x(x² + x - 1) - 8(x² + x - 1) ← distribute both parenthesis
= x³ + x² - x - 8x² - 8x + 8 ← collect like terms
= x³ - 7x² - 9x + 8 → A
There are no restrictions on the domain.
Answer:
i think the best estimate is answer b
Step-by-step explanation:
Answer:
The last one
Step-by-step explanation:
measure angle 2 and 6 to see if congruent
Answer:
No it is not.
Step-by-step explanation:
Reason.
For geometric: common ratio r should be equal
r = T2/T1 = T3/T2 but is not true here as -6/-14 is not equal to 2/-6
