Answer:
there are 7 significant figures
Explanation:
15.33879+15.555
=30.89379
there are 7 significant figures
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Answer:
-0.038 N
Explanation:
F=K Q1 Q2/r^2 by COULOMB'S LAW
F= 9×10^9×1×10^-5×-1.5×10^-5/(6)^2
F= -0.038 N
We have that the instantaneous velocity of the
shuttlecock when it hits the ground is

From the question we are told
Assuming the acceleration is still -9.81 m/s2, what is the instantaneous velocity of the
shuttlecock when it hits the ground? Show your work below.
Generally the equation for acceleration is mathematically given as

Where
acceleration is still -9.81 m/s2,
Hence,

Therefore

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<h3>Answer:</h3>
- 24.5 km/h
- 4 17/27 m/s
- 11/3 m/s²
<h3>Explanation:</h3>
1. The average speed is the ratio of total distance to total time:
... speed = distance/time = (92 km +55 km)/(3 h +3h) = (147 km)/(6 h)
... = 24.5 km/h
2. speed = distance/time = (125 m)/(27 s) = 4 17/27 m/s
3. a = ∆v/∆t = (15 m/s -4 m/s)/(3 s) = 11/3 m/s²