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Lubov Fominskaja [6]
3 years ago
13

Please help I have a time limit of 15 minutes and I only have 5 left

Physics
2 answers:
VikaD [51]3 years ago
5 0
I remember this it’s vest
o-na [289]3 years ago
4 0

Answer: I'm pretty sure it's either crest or trough... So, the official answer is Crest because this picture helped me...

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Sound travels faster in: steel water sir
alukav5142 [94]
Sound travels better in water
8 0
3 years ago
A garage door opener has a power rating of 350 watts.
Lelechka [254]
We Know, Power = Energy/Time
Substitute the known value. which is P = 350 watt, & T = 30 sec
350 = E/30 
E = 350 * 30
E = 1050 Joules.

So, your answer is 1050 Joules.
Hope this helps! Keep studying! 
6 0
3 years ago
Read 2 more answers
At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis. People sit in seats faci
ozzi

Answer:

r=2.4m

Explanation:

We have to use the centripetal force  equation

Fc=\frac{mv^{2} }{r}

we  need the radious so we have to isolate "r" and we get

r=\frac{mv^{2} }{Fc}

replacing m=65 kg, v= 4.1 m/s and Fc=455N we get

r=\frac{65*4.1^{2} }{455}

r=2.4m

The radius of the amusement park chamber is 2.4m

4 0
3 years ago
What is the weight of a feather (mass = 0.0001 kg) that floats through earth's and the moon's atmospheres?
Dvinal [7]

Weight = (mass) x (acceleration of gravity)

Acceleration of gravity = 9.81 m/s² on Earth, 1.62 m/s² on the Moon.

The feather's weight is . . .

On Earth:  (0.0001 kg) x (9.81 m/s²) = <em>0.000981 Newton </em>

On the Moon:  (0.0001 kg) x (1.62 m/s²) = <em>0.000162 N</em>

The presence or absence of atmosphere makes no difference.  In fact, the numbers would be the same if the feather were sealed in a jar, or spinning wildly in a tornado, or hanging by a thread, or floating in a bowl of water or chicken soup.  Weight is just the force of gravity between the feather and the Earth.  It's not affected by what's around the feather, or what's happening to it.

6 0
3 years ago
If an X-ray tube is operating at a current of 30.0 mA:a) How many electrons are striking the target per second? b) If the potent
Zina [86]

Answer:

Explanation:

A. Q= It

30E-3A=q

Ne = q

30E-3/1.6*10-19= N

N= 1.8*10^16 electrons

B. Power= I x v

= 30*10^-3A x 100*10^3v

= 3000watts

3 0
3 years ago
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