The speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
<h3>Relative velocity of the car</h3>
The speed of the car passing you is determined by applying relative velocity principle as shown below;
Vr = Va - Vb
Vr = 26 m/s - 32 m/s
Vr = -6 m/s
Thus, the speed of the car passing you is 6 m/s while car is moving 6 m/s behind the car.
Learn more about relative velocity here: brainly.com/question/17228388
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Answer:
The average acceleration is 16.6 m/s² ⇒ 1st answer
Explanation:
A rocket achieves a lift-off velocity of 500.0 m/s from rest in
30.0 seconds
The given is:
→ The initial velocity = 0
→ The final velocity = 500 meters per seconds
→ The time is 30 seconds
Acceleration is the rate of change of velocity of the rocket
→ 
where a is the acceleration, v is the final velocity, u is the initial velocity
and t is the time
→ u = 0 , v = 500 m/s , t = 30 s
Substitute these values in the rule
→ 
m/s²
<em>The average acceleration is 16.6 m/s²</em>
A) atomic number 7
B) 15
C) 6 c, 12 h, 6 o
D) o-8
S-16
Answer: 180N/m(to 2 significant figures)
Explanation:
According to hooked law which states that the extension of a material is directly proportional to the applied force provided that the elastic limit is not exceeded. Mathematically, F = ke where;
F is the applied force in newtons
k is the elastic/spring constant in N/m
e is the extension in meters
Given applied force = 35N
extension = 20cm = 0.2m
Since F = ke,
k = F/e = 35/0.2
k = 175N/m
The spring constant is 175N/m
= 180N/m (to 2significant figures)
