Answer:
IT feels proud to be done making a bridge
Explanation:
My favorite movie is rundown for sure
Answer:
The amplitude of the absorbed mass can be found
for ka:

now
![w^2=\frac{K_{a} }{m_{a} } \\m_{a} =\frac{K_{a} }{w^2} =\frac{125000}{[6000*2\pi /60]^2} =0.317kg](https://tex.z-dn.net/?f=w%5E2%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bm_%7Ba%7D%20%7D%20%5C%5Cm_%7Ba%7D%20%3D%5Cfrac%7BK_%7Ba%7D%20%7D%7Bw%5E2%7D%20%3D%5Cfrac%7B125000%7D%7B%5B6000%2A2%5Cpi%20%2F60%5D%5E2%7D%20%3D0.317kg)
Answer:


Given:

operating temperature of heat engine, 

Solution:
For a reversible cycle, maximum efficiency,
is given by:



Now, on re designing collector, maximum temperature,
changes to
, so, the new maximum efficiency,
is given by:



Answer:
The displacement from t = 0 to t = 10 s, is -880 m
Distance is 912 m
Explanation:
. . . . . . . . . . A
integrate above equation we get

from information given in the question we have
t = 1 s, s = -10 m
so distance s will be
-10 = 12 - 1 + C,
C = -21

we know that acceleration is given as
[FROM EQUATION A]
Acceleration at t = 4 s, a(4) = -24 m/s^2
for the displacement from t = 0 to t = 10 s,

the distance the particle travels during this time period:
let v = 0,

t = 2 s
Distance ![= [s(2) - s(0)] + [s(2) - s(10)] = [1\times 2 - 2^3] + [(12\times 2 - 2^3) - (12\times 10 - 10^3)] = 912 m](https://tex.z-dn.net/?f=%3D%20%5Bs%282%29%20-%20s%280%29%5D%20%2B%20%5Bs%282%29%20-%20s%2810%29%5D%20%3D%20%5B1%5Ctimes%202%20-%202%5E3%5D%20%2B%20%5B%2812%5Ctimes%202%20-%202%5E3%29%20-%20%2812%5Ctimes%2010%20-%2010%5E3%29%5D%20%3D%20912%20m)