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VARVARA [1.3K]
3 years ago
13

Refrigerant-134a enters an adiabatic compressor at -30oC as a saturated vapor at a rate of 0.45 m3 /min and leaves at 900 kPa an

d 55oC. Determine (a) the power input to the compressor, (b) the isentropic efficiency of the compressor, and (c) the rate of exergy destruction and the second-law efficiency of the compressor. Take T0
Engineering
1 answer:
saw5 [17]3 years ago
4 0

Answer:

a) 1.918 kw

b) 86.23%

c) 0.26 kw

Explanation:

Given data:

T1 = -30°C = 243 k  , T0 = 27°C

using steam tables

h1 = 232.19 KJ/kg

s1 = 0.9559 Kj/Kgk

T2 = 55°C   P2 = 900 kPa

Psat = 1492 kPa,  h2 = 289.95 Kj/Kg, s2 = 0.9819 Kj/kgk , m = 0.0332 kg/s

<u>a) Determine the power input to the compressor</u>

power input = 1.918 kw

<u>b) Determine isentropic efficiency of compressor</u>

Isentropic efficiency = 86.23%

<u>c) Determine rate of exergy destruction</u>

rate = 0.26 kw

Attached below is the detailed solution of the given problems

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\eta _{max} = 0.2413 = 24.13%

\eta' _{max} = 0.5061 = 50.61%

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T_{1max} = 100^{\circ} = 273 + 100 = 373 K

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For a  reversible cycle, maximum efficiency, \eta _{max} is given by:

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Now, on re designing collector, maximum temperature, T_{3max} changes to 300^{\circ}, so, the new maximum efficiency,  \eta' _{max} is given by:

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4 years ago
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Answer:

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the distance the particle travels during this time period:

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4 years ago
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