Answer:
technician A is correct
Explanation:
Technician B has circuit topologies confused. In a series circuit, there is only one path for electrical current to take. In a parallel circuit, the current will divide between paths in proportion to the inverse of their resistance. The least resistance path will have the most current.
Technician A is mostly correct.
Answer:
a) 23.551 hp
b) 516.89 hp
Explanation:
<u>given:</u>

<u>required:</u>
the power in hp
<u>solution:</u>
.............(1)
by substituting in the equation (1)
=353.27 lbf
..........(2)
by substituting in the equation (2)
= 2769.29 lbf
power is defined by
P=F.V
353.27*36.67
=12954.411 lbf.ft/s
=12954.411*.001818
=23.551 hp
2769.29*102.67
= 284323 lbf.ft/s
= 284323*.001818
= 516.89 hp
Answer:
hello your question is incomplete attached below is the complete question
A) optimum compressor ratio = 9.144
B) specific thrust = 2.155 N.s /kg
C) Thrust specific fuel consumption = 1670.4 kg/N.h
Explanation:
Given data :
Mo = 2.1 , To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k
γ = 1.4
attached below is the detailed solution
Answer:
If the heat engine operates for one hour:
a) the fuel cost at Carnot efficiency for fuel 1 is $409.09 while fuel 2 is $421.88.
b) the fuel cost at 40% of Carnot efficiency for fuel 1 is $1022.73 while fuel 2 is $1054.68.
In both cases the total cost of using fuel 1 is minor, therefore it is recommended to use this fuel over fuel 2. The final observation is that fuel 1 is cheaper.
Explanation:
The Carnot efficiency is obtained as:

Where
is the atmospheric temperature and
is the maximum burn temperature.
For the case (B), the efficiency we will use is:

The work done by the engine can be calculated as:
where Hv is the heat value.
If the average net power of the engine is work over time, considering a net power of 2.5MW for 1 hour (3600s), we can calculate the mass of fuel used in each case.

If we want to calculate the total fuel cost, we only have to multiply the fuel mass with the cost per kilogram.

<u>Answer:</u>
<u>of 150 pounds per square inch</u>
Explanation:
Note that the unit for measuring water pressure is called <u> pounds per square inch (psi)</u>
In the case of sprinklers and standpipe systems, a pressure <u>of 150 pounds per square inch</u> was used initially.