A robot's work envelope is its range of movement. It is the shape created when a manipulator reaches forward, backward, up and down. These distances are determined by the length of a robot's arm and the design of its axes. ... A robot can only perform within the confines of this work envelope.
The classical motion for an oscillator that starts from rest at location x₀ is
x(t) = x₀ cos(ωt)
The probability that the particle is at a particular x at a particular time t
is given by ρ(x, t) = δ(x − x(t)), and we can perform the temporal average
to get the spatial density. Our natural time scale for the averaging is a half
cycle, take t = 0 → π/
ω
Thus,
ρ =
Limit is 0 to π/ω
We perform the change of variables to allow access to the δ, let y = x₀ cos(ωt) so that
ρ(x) =
Limit is x₀ to -x₀
Limit is -x₀ to x₀
This has as expected. Here the limit is -x₀ to x₀
The expectation value is 0 when the ρ(x) is symmetric, x ρ(x) is asymmetric and the limits of integration are asymmetric.
Answer:
they are important together, but if you want to use just one future you must think about which one is first needed. and then try to learn for economical so don't use more money
Answer:240m
Explanation:
Given rpm increases from 1750 rpm to 3500 rpm
initial head 60 m and flow rate=
Since unit speed remains same
therefore
=
H=240m
Also unit Flow remains same
=
=
The total rate of energy emission is 2786.9 W.
<h3>Total Rate of Energy Emission</h3>
Radiation is a type of heat transfer where the heat energy is conveyed from photons or electromagnetic waves. The rate of energy emission can be calculated multiplying the Stefan–Boltzmann law (σ) by area (A). Therefore, you have:
Total Rate of Energy Emission (E)= σ, where:
σ = Stefan–Boltzmann constant =
A= area
T=temperature (K)
For solving this exercise, you should apply this formula. For your question:
σ = Stefan–Boltzmann constant =
A= 0.12 m²
T=527+273=800 K
Thus, the Total Rate of Energy Emission (E) will be:
E=σ
Read more about radiation heat transfer about:
brainly.com/question/16191304